You want the equation for a line that goes through the data points (0, 248) and (5, 277). The slope is ∆y/∆x = (277-248)/(5-0) = 29/5 = 5.8. The first data point is the y-intercept, so your equation in slope-intercept form is
... y = 5.8x + 248 . . . . . . where y is MWh of generation and x is years since 2007.
_____
∆y is read "delta y". It means "the change in y".
Answer:
The value that appears more
Step-by-step explanation:
Hope u get it right!:D
32-15=17
please my answer!!1111!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
<span>i think its the outcomes do not appear to be equally likely, so a uniform probability model is not a good model to represent probabilities in Tessa's experiment.<span>
</span></span>
(1 point) let a=(2,4,−5)a=(2,4,−5), b=(−3,6,−5)b=(−3,6,−5), c=(−8,7,0)c=(−8,7,0), and d=(−3,5,0)d=(−3,5,0). find the area of the
maksim [4K]
Areas and volumes of parallelograms and parallelepipeds in 3 dimensions are often easily found by making use of the cross product of the direction vectors of their edges. For edge vectors v1 and v2 of a triangle, the area is ...
... A = (1/2)║v1 × v2║
that is, half the norm of the cross-product vector. The area of a parallelogram with those edge vectors is simply ...
... A = ║v1 × v2║
Here, direction vectors are ...
- ab = (-5, 2, 0)
- bc = (-5, 1, 5)
- cd = (5, -2, 0)
- da = (5, -1, -5)
We can see that ab = -cd and bc = -da, as required for a parallelogram.
The cross product ab × bc is (10, 25, 5), so the area of the parallelogram is
... ║(10, 25, 5)║ = √(10² +25² +5²) = √750
... Area = 5√30 ≈ 27.3861 . . . . square units (parallelogram area)
The areas of each of the mentioned triangles is half the area of the parallelogram, so is
... Area Δabc = Area ∆abd = (5/2)√30 ≈ 13.6931 . . . . square units (triangles)
