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tekilochka [14]
4 years ago
9

5c-1÷4=4+10c÷9 is there a solution or no solution and if there is I would like to see the steps in solving this equation so I ca

n show the steps on my paper.

Mathematics
1 answer:
vekshin14 years ago
6 0

I don’t think this will help exactly but I hope it does x

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The lengths of the sides of a triangle are 9​, 12​, and 15. Classify the triangle as​ acute, right, or obtuse.
Stells [14]

Answer:

right angle triangle

Step-by-step explanation:

by applying Pythagoras theorem

RHS ={9}^{2}  + 12 ^{2}  =   81 + 144 = 225=√225 =15=LHS

hence proved

6 0
2 years ago
1 - 2.25x^8<br> Factor this
Yuliya22 [10]

Answer:

(1+3/2x^4)(1-3/2x^4) = (1+1.5x^4)(1-1.5x^4)

Step-by-step explanation:

2.25 = 9/4

putting decimals into fractions will make this easier

9/4 = 3/2 * 3/2

a²-b² = (a+b)(a-b)

1 - 2.25x^8 = 1²-(3/2x^4)² = (1+3/2x^4)(1-3/2x^4) = (1+1.5x^4)(1-1.5x^4)

7 0
4 years ago
A recipe for whole grain rolls calls for 3/4 cup of flour. The recipe makes 6 rolls .How many cups is needed for 32 Rolls?
aalyn [17]
32/6 = 16/3 = 5.33

.75 x 5.33 = 4 cups of rye flour.
3 0
3 years ago
25 times what is fifty?
masha68 [24]

Answer:

2

Step-by-step explanation:

4 0
4 years ago
SOMEONE HELP ASAP!!
Anuta_ua [19.1K]

9514 1404 393

Answer:

  (c)  dZ/dt = 11/√544, so moving away at about 0.47 m/s

Step-by-step explanation:

The (x, y) coordinates of the car are related by the fact that they are on a circle centered at (12, 7) with a radius of 5. Then their rates of change are related by the derivative of the circle equation with respect to time.

  (x -12)^2 + (y -7)^2 = 25

  2(x -12)x' +2(y -7)y' = 0

  y' = -(x -12)/(y -7)x'

At the time and point of interest, we have ...

  y' = -(15 -12)/(11 -7)(1) = -3/4

__

The distance (z) to the observer is given by the Pythagorean theorem:

  z^2 = (x -0)^2 +(y -2)^2

and its rate of change with time is ...

  2z·z' = 2(x-0)x' +2(y -2)y'

The distance d at the point of interest is ...

  z = √((15 -0)^2 +(11 -2)^2) = √(225 +81) = √306 = 3√34

So, the rate of change of distance to the observer at the time and point of interest is ...

  z' = (x(x') +(y -2)y')/z

  z' = ((15)(1) +(11-2)(-3/4))/(3√34) = (33/4)/(3√34)

  z' = 11/√544 ≈ 0.47 . . . m/s

3 0
3 years ago
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