3/5 squared in 9/25, 3*3/5*5 :)
The equation we will use here is A^2+B^2=C^2, which is also know as the Pythagorean Theorem.
The given values are 6 and 9, where they can represent any value, there true values in the equation would be 36(6), and 81(9), so you must select a value that makes the equation true, given the constraints.
with that being said 3, doesnt work because
·36(6)+9(3)≠81(9)
·9(3)+81(9)≠36(6)
·36(6)+81(9)≠9(3)
10 doesnt work either because
·36(6)+81(9)≠100(10)
·81(9)+100(10)≠36(6)
·100(10)+36(6)≠81(9)
12 doesnt work either because
·144(12)+36(6)≠81(9)
·36(6)+81(6)≠144(12)
·81(9)+144(12)≠36(6)
If you see where this is going you would know that there is no valid solution here, however rounding is always a possibility, when you actually do the math 81(9)+36(6)=117, and when squared you get your answer of 10.8, and the closest answer is 10, there fore your answer would be 10
-I hope this is the answer you are looking for, feel free to post your questions on brainly at any time.
Answer:
hi
Step-by-step explanation:
i think so…
I really hope this helps.
Answer:
p = 3
Step-by-step explanation:
5p+8 = 7p+2 (subtract boths sides by 2 and 5p)
6 = 2p (Divide both sides by 2)
p = 3
