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3 years ago

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James Works in a flower shop he will put 27 tulips in vases for a wedding he must use the same number of tulips in each vase the

number of tulips in each vase must be greater than 1 and less than 10 how many tulips could be in each vase

1 answer:

Svetllana [295]3 years ago

3 0

Umm..can you help i dont get it.

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A person who is 6ft tall walks away from a streetlight. When the person is 15 feet away from the light, the tip of his shadow is

Citrus2011 [14]

We essentially have a ratio here:
$\frac{shadow}{actual}$

Since we know the ratio is going to stay constant at $\frac{5}{6}$ , we can use this to find the height of the lamp along with the information that the total distance from the lamp to the tip of his shadow is 20:
$\frac{5}{6}=\frac{20}{h}$
$5h=120$
$h=24$

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3 years ago

if a single card is drawn from a standard 52- card deck in how many ways can a card other than a heart be obtained

dmitriy555 [2]

Answer:

there would be a 1-51 chance most likely

Step-by-step explanation:

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3 years ago

Read 2 more answers

A) A square has an area of 64 cm?

kolbaska11 [484]

Answer:

perimeter of square =34cm

Step-by-step explanation:

its 64..area

normally we find area by calculating side ×side

so 8×8

=64

so its 34cm....

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3 years ago

When we toss a coin, there are two possible outcomes: a head or a tail. Suppose that we toss a coin 100 times. Estimate the appr

marin [14]

Answer:

96.42% probability that the number of tails is between 40 and 60.

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

100 tosses, so $n = 100$

Two outcomes, both equally as likely. So $p = \frac{1}{2} = 0.5$

So

$E(X) = np = 100*0.5 = 50$

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{100*0.5*0.5} = 5$

Estimate the approximate probability that the number of tails is between 40 and 60.

Using continuity correction.

$P(40 - 0.5 \leq X \leq 60 + 0.5) = P(39.5 \leq X \leq 60.5)$

This is the pvalue of Z when X = 60.5 subtracted by the pvalue of Z when X = 39.5. So

X = 60.5

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{60.5 - 50}{5}$

$Z = 2.1$

$Z = 2.1$ has a pvalue of 0.9821

X = 39.5

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{39.5 - 50}{5}$

$Z = -2.1$

$Z = -2.1$ has a pvalue of 0.0179

0.9821 - 0.0179 = 0.9642

96.42% probability that the number of tails is between 40 and 60.

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3 years ago

Find the values of x and y.

gogolik [260]

Answer:

If you have given an equation, you see the x and y in it. Just taking second equation and think any common factor between x's variable. With common factor, multiply both and you will find the value of y and put it in any equation, you will find the value of X.

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