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3 years ago

13

Line passes throught (2,2) and is perpendicular to Y=3X+7

2 answers:

Sergio [31]3 years ago

8 0

For this question you would need to use point-slope form which is: (y-y₁)=m(x-x₁) where m=slope and (x₁, y₁) is your point on the line. So you already have a point, (2,2) and you need slope which is the negative inverse of the slope of a line perpendicular to it. In this case, the slope would be -1/3. So if you plug all of this in the point-slope equation you get: y-2=(-1/3)(x-2) ------> y=(-1/3x)-(2/3)+2 ----------------->y=(-1/3x)+(4/3)

DanielleElmas [232]3 years ago

6 0

Y-2=-1/3(x-2)
y-2=1/3x+2/3
y=-1/3x+8/3

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Liono4ka [1.6K]

Answer:

Your answer should be $29.40

Step-by-step explanation:

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3 years ago

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3 years ago

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Charra [1.4K]

Answer:

$log_{100}20 = 0.6505$

Step-by-step explanation:

log20 = 1.301 (when you see only "log" with no base, it is taken as a base 10)

This basically means:

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Since we don't know what $log_{100}20$ is equal to, we will say $log_{100}20$ = x

So to solve for $log_{100}20$ = x, you do the same thing. (convert to exponential form)

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Now you will notice that both of these equations are equal to 20.

Since 20 = 20,

we can say $100^{x}$ = $10^{1.301}$

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Now we get $10^{2x} = 10^{1.301}$

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3 years ago

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nadezda [96]

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3 years ago

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Vika [28.1K]

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3 years ago