$\bf \sqrt{\cfrac{100}{144}}~~
\begin{cases}
100=10\cdot 10\\
\qquad 10^2\\
144=12\cdot 12\\
\qquad 12^2
\end{cases}\implies \sqrt{\cfrac{10^2}{12^2}}\implies \cfrac{10}{12}\implies \stackrel{simplified}{\cfrac{5}{6}}$

6 0

4 years ago

The parking space shown on the right has an area of 216 ft². A custom truck has rectangular dimensions of 12.1 ft by 3.6 ft. Can

mart [117]

Answer:

• Yes, the area of the truck is less than the area of the parking space.

• The missing dimension of the parking space is 12 ft.

Explanation:

The area of the parking space = 216 ft²

Part A

The dimensions of the custom truck = 12.1 ft by 3.6 ft.

To determine if the truck can fit into the space, we calculate the area of the truck.

$\begin{gathered} \text{Area of the truck}=12.1\times3.6 \\ =43.56ft^2 \end{gathered}$

Since the area of the truck is less than the area of the parking space, the truck will fit into the space.

Part B

The parking space is in the shape of a parallelogram.

$\text{Area of a parallelogram=Base x Perpendicular Height}$

Given:

• Area = 216 ft²

• Base = b ft

• Perpendicular Height = 18 ft

We then have:

$\begin{gathered} 216=b\times18 \\ 18b=216 \\ b=\frac{216}{18} \\ b=12\text{ ft} \end{gathered}$

The missing dimension of the parking space is 12 feet.

7 0

2 years ago

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Solve this sum urgent no spam