An infinite amount...since there ARE and infinite amount of number in the universe.
1111
2222
3333
4444
5555
6666
7777
8888
9999
1010
1234
4321
5432
2345
5678
8765
0987
7890
4509
9054
Etc
Answer:
Jocelyn's plane travelled 3650 miles.
Step-by-step explanation:
mph stands for miles per hour.
Let's set up an equation.
total miles = speed(hours)
Jocelyn's plane travelled 500 mph for 7.3 hours.
total miles = 500(7.3)
Multiply.
total miles = 3650
Jocelyn's plane travelled 3650 miles.
Hope this helps!

Let's solve ~
Total Mini - Easter eggs = 1345
Number of students = 26
So, let's find how many eggs will each student get through division ~

So, each student will get 51 mini - Easter egg each.
And there would be 19 remaining eggs in there ~
Answer:
m>14 or m< -2
Step-by-step explanation:
1) To find the confidence interval
the sample mean x = 38 σ = 9; n = 85;
The confidence level is 95% (CL = 0.95) <span>CL = 0.95
so α = 1 – CL = 0.05
</span><span>α/2 = 0.025 </span>Z(α/2) = z0.025
The area to the right of Z0.025 is 0.025 and the area to the left of Z0.025 is 1 – 0.025 = 0.975
Z(α/2) = z0.025 = 1.645 This can be found using a computer, or using a probability table for the standard normal distribution.
<span>EBM = (1.645)*(9)/(85^0.5)=1.6058</span> x - EBM = 38 – 1.6058 = 36.3941 <span> x + EBM = 38 + 1.6058 = 39.6058
</span>The 95% confidence interval is (36.3941, 39.6058).
The answer is the letter D
<span>The value of 40.2 is <span>within the 95% confidence interval for the mean of the sample
</span></span>2) To find the confidence interval <span>
<span>the sample mean x = </span>76 σ = 20; n = 102; </span><span>
The confidence level is 95% (CL = 0.95) CL = 0.95
so α = 1 – CL = 0.05
α/2 = 0.025 Z(α/2) = z0.025
The area to the right of Z0.025 is 0.025 and the area to the
left of Z0.025 is 1 – 0.025 = 0.975
Z(α/2) = z0.025 = 1.645 This can be found using a computer,
or using a probability table for the standard normal distribution.
EBM = (1.645)*(20)/(102^0.5)=3.2575 x - EBM = 76 – 3.2575 = 72.7424 </span> x +
EBM = 76 + 3.2575 = 79.2575 <span>
The 95% confidence interval is (</span>72.7424 ,79.2575).<span>
The answer is the letter </span>A
and the letter D<span>
The value of 71.8 and 79.8 <span> are </span> outside<span>
the 95% confidence interval for the mean of the sample</span></span>