For First Question:
As, we find the value of x for parallel condition of line a and b
so, m∠3 = m∠1 and m∠2 = 180°-m∠1 = 180°-(2x+15)° [ As straight line contain total 180°]
Now,
m∠2 = <span>m∠6 [ Because they are corresponding angles]
180</span>-(2x+15)=(3x+10)
180=3x+10+2x+15
x= 31 satisfies the condition of a||b
For second Question:
As, it is issoceles triangle So side AC = side BC So, m∠A=<span>m∠B
</span>4x+5=5x-1
x=6
So,
m∠A=29° and triangle contain total 180°
<span>m∠C=180-29-29
</span> =122°
Option D is correct
<span>We use the symbol %<span> for "percent."</span></span>
<span>The word "percent" really just means "per hundred.</span>
47.5 cause in the two total rotations, it was 95 so you would divided 95 by two and get 47.5.
Answer:
p < 8
Step-by-step explanation:
3p+7<31
Subtract 7 from each side
3p+7-7<31-7
3p <24
Divide each side by 3
3p/3 <24/3
p < 8
Answer/Step-by-step explanation:
Given:
m<EFH = (5x + 1)°
m<HFG = 62°
m<EFG = (18x + 11)°
Required:
1. Value of x
2. m<EFH
3. m<EFG
SOLUTION:
1. Value of x
m<EFH + m<HFG = m<EFG (angle addition postulate)
(5x + 1) + 62 = (18x + 11)
Solve for x using this equation
5x + 1 + 62 = 18x + 11
5x + 63 = 18x + 11
Subtract 18x from both sides
5x + 63 - 18x = 18x + 11 - 18x
-13x + 63 = 11
Subtract 63 from both sides
-13x + 63 - 63 = 11 - 63
-13x = -52
Divide both sides by -13
-13x/-13 = -52/-13
x = 4
2. m<EFH = 5x + 1
Plug in the value of x
m<EFH = 5(4) + 1 = 20 + 1 = 21°
3. m<EFG = 18x + 11
m<EFG = 18(4) + 11 = 72 + 11 = 83°
