On #29 x = 12 and <apb = 90° and <dcb = 40° and on #30 all I dont even understand, sorry
The answer:
the full question is as follow:
<span>Point F is on circle C. What is the length of line segment GF?
12.5 units
15.0 units
17.5 units
20.0 units
according to the image, GF= GC + CF
CF is the radius of the circle, so it is CF =CE = 7.5
all that we want to find is the value of GC
let's consider the triangle GEC. This is a right triangle, so for finding GC, we can apply Pythagorean theorem
that is, GE² + EC² = GC², and from this, we have GC = sqrt(</span>GE² + EC² )
GC = sqrt(10² + 7.5² )=sqrt(56.25)=12.5
<span>
therefore, </span>GF= GC + CF=12.5 + 7.5 = 20.0
the answer is 20.0 units
240 bc you need to mulitpy it and ye
Answer:
y=5sin(16pix)+3
Step-by-step explanation:
Amp=5 means our curve is either y=5sin(bx+c)+d or y=-5sin(bx+c)+d.
y=sin(x) has period 2pi.
So y=sin(bx) has period 2pi/b.
We want 2pi/b=1/8.
Cross multiplying gives: 16pi=b
y=5sin(16pix+c)+d
d=3 since we want midline y=3.
y=5sin(16pix+c)+3
We can choose c=0 since we aren't required to have a certain phase shift.
y=5sin(16pix)+3
