Solve 7x + 6 > 1 + 2x

2 answers:

8 0

Here we have an inequality in terms of x, with x on both sides. However, we can treat it as a straightforward equation in as much as we can use our standard operations as long as we do the same to both sides. Here, as we want to get all the terms with x on the same side, and everything else on the other (as we are solving an inequality in terms of x after all), we can subtract 2x from both sides, and subtract 6 from sides. This leaves us the new inequality (which means the same) of 5x>-5. We can simplify this further by dividing each side by 5, leaving x>-1, which is our final answer. We can show this on a graph also, if asked, like so...

professor190 [17]3 years ago

5 0

7x+6>1+2x

subtract 2x from each side:

5x+6>1

subtract 6 from each side:

5x>-5

divide each side by 5:

x>-5/5

x>-1

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In a basketball game, Team A defeated Team B with a score of 97 to 63. Team A won by scoring a combination of two-point baskets,

-BARSIC- [3]

Answer:

14 free throw baskets , 25 two point baskets and 11 three point baskets

Step-by-step explanation:

Let n₁ represent the number of free-throw baskets, n₂ represent the number of two point baskets and n₃ represent the number of three point baskets.

Now, from the question, the number of two point baskets, n₂ is greater than the free throw baskets by 11. This is written as n₂ = n₁ + 11. Also, the number of three point baskets n₃ is three less than the number of free point baskets. This is written as n₃ = n₂ - 3. Since our total number of points equals 97, it follows that, sum of number of points multiplied by each point equals 97. So, ∑(number of points × each point) = 97. Thus,

n₁ + 2n₂ + 3n₃ = 97. Substituting n₂ and n₃ from above, we have n₁ +2(n₁ + 11) + 3(n₁ - 3) = 97.

Expanding the brackets, we have, n₁ + 2n₁ + 22 + 3n₁ - 9 = 97

collecting like terms, we have 6n₁ + 13 = 97

6n₁ = 97 - 13

6n₁ = 84

dividing through by n₁ we have, n₁ = 84/6 =14

so n₁ our free throw baskets equals 14. Substituting this into n₂ our number of two point baskets equals n₂ = n₁ + 11 = 14 + 11 = 25. Our number of three point baskets n₃ = n₁ - 3. So, n₃ = 14 -3 = 11.

7 0

3 years ago

Read 2 more answers

How many ways can 6 people be chosen and arranged in straight line if there are 8 people to choose from? a. 48.b. 720.c. 20, 160

Ipatiy [6.2K]

Answer:

Step-by-step explanation:

This question bothers on permutation since we are to select a some people out of a group of people and then arrange in a straight line. If r object are to be arranged in a straight line when selecting them from n pool of objects. This can be done in nPr number of ways.

nPr = n!/(n-r)!

Selection of 6 people out of 8 people can therefore be done in 8C6 number of ways.

8P6 = 8!/(8-6)!

8P6 = 8!/2!

8P6 = 8*7*6*5*4*3*2!/2!

8P6 = 8*7*6*5*4*3

8P6 = 56*360

8P6 = 20,160

<em>Hence this can be done in 20,160 number of ways</em>

5 0

3 years ago

What are the roots of the equation? x^2+24=14×