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Effectus [21]
2 years ago
6

Name of polygon by using 3 rhombus

Mathematics
1 answer:
Mrrafil [7]2 years ago
3 0
Squares, rectangles, and parallelograms.
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Rewrite x - 2y = 8 using function notation.
Vadim26 [7]
Isolate for y.
x - 2y =8
x-8 = 2y
(x-8)/(2) = y
(x/2) - (8/2) = y
y = (1x/2) - (4)

f(x) = (1/2)x - 4
The answer is D.
7 0
3 years ago
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Lily plays tennis, golf, ping pong, and volleyball. Do more or less than 2/4 of the sports lily plays use a net?
Tems11 [23]

Answer:

Out of the 4 sports only golf does not use a net. Therefore 3/4 is the sports uses a net

The answer is more than 2/4 of the sports

Hope this helps!

6 0
2 years ago
PLEASE PLEASE ANSWER
saul85 [17]

Answer:

Step-by-step explanation:

So the sum of 128 and x+10 is on a straight line which is 180º right?, so:

x + 10 + 128 = 180

x = 180 - 128 - 10

x = 42º

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2 years ago
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A cost center’s performance report does not include
Ymorist [56]

Answer:

‎‎‎‎‎

Step-by-step explanation:

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7 0
2 years ago
How to find the x-intercepts of a parabola from the vertex, (-1,-108) and the y intercept (0,-105)?
Ulleksa [173]

Answer:

* The x-intercepts are -7 and 5

Step-by-step explanation:

* At first lets revise the standard and general forms of the

 quadratic function which represented graphically by the parabola

- f(x) = a(x - h)² + k ⇒ standard form

- Where point (h , k) is the vertex of the parabola

- f(x) = ax² + bx + c ⇒ general form

- Where a, b, c are constant

- c is the y-intercept ⇒ means x = 0

- h = -b/2a

- k = f(h)

* Lets solve the problem

- We will find the equation of the parabola

∵ The vertex is (-1 , -108)

∴ h = -1 and k = -108

∵ y-intercept = -105

- Equate the two forms

∵ ax² + bx + c = a(x - h)² + k ⇒ solve the (   )²

∴ ax² + bx + c = a(x² - 2hx + h²) + k ⇒ open the bracket

∴ ax² + bx + c = ax² - 2ahx + ah² + k ⇒ by comparing the two sides

∴ c = ah² + k

- Substitute the value of c , h , k in it

∴ -105 = a(-1)² + -108

∴ -105 = a - 108 ⇒ add 108 to the both sides

∴ 3 = a

- Lets write the equation in the standard form

∴ y = 3(x - -1)² + -108

∴ y = 3(x + 1)² - 108

* To find the x-intercepts means the parabola intersects the x-axis,

  then put y = 0

∴ 3(x + 1)² - 108 = 0 ⇒ Add 108 to the both sides

∴ 3(x + 1)² = 108 ⇒ divide the both sides by 3

∴ (x + 1)² = 36 ⇒ take square root for both sides

∴ (x + 1) = ± 6

# x + 1 = 6  OR x + 1 = -6

∵ x + 1 = 6 ⇒ subtract 1 from both sides

∴ x = 5

∵ x + 1 = -6 ⇒ subtract 1 from both sides

∴ x = -7

* The x-intercepts are -7 and 5

∴

3 0
2 years ago
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