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melomori [17]
3 years ago
14

Whats 1x to the 3rd power and y to the third power divided by 3x squared and y to the 4th power

Mathematics
1 answer:
Alex787 [66]3 years ago
6 0
The answer would be 1 by 3 y to the first power
You might be interested in
Which of the following is an equivalent form of the compound inequality −22 > −5x − 7 ≥ −33?
alexgriva [62]

An equivalent form of the compound inequality −22 > −5x − 7 ≥ −33 will be −5x − 7 > −22 and −5x − 7 ≥ −33

<h3>Compound inequality</h3>

A compound inequality (or combined inequality ) is two or more inequalities joined together with inequality operations.

Given the compound inequality −22 > −5x − 7 ≥ −33, this can also be splitted into;

−22 > −5x − 7 and  −5x − 7 ≥ −33,

The inequality expression  −22 > −5x − 7 is also expressed as  −5x − 7 > -22. Hence an equivalent form of the compound inequality −22 > −5x − 7 ≥ −33 will be −5x − 7 > −22 and −5x − 7 ≥ −33

Learn more on compound inequality here: brainly.com/question/1485879

#SPJ1

3 0
1 year ago
What is an equation of the line that passes through the points (7, 4) and ( -5, 4)?
Sedaia [141]

Answer:

y = 4

Step-by-step explanation:

To find the slope, you plug the coordinates into the slope formula.

y2 - y1/ x2 - x1

= 4 - 4/ -5 - 7

= 0

The slope is 0.

To find the y-intercept, y = 0x + b

4 = 0(7) + b

4 = 0 + b

4 = b

The equation is y = 4

6 0
3 years ago
-8x + 2x -16 &lt; -5x + 7x<br><br> could you explain the answer
tigry1 [53]

Answer:

x > -2

Step-by-step explanation:

First, you simplify both sides of the inequality by combining like terms

-8x + 2x -16 < -5x + 7x

-6x - 16 < 2x

Then, you add 6x to both sides in order to isolate x (bring all the Xs to one side)

-6x - 16 + 6x < 2x + 6x

-16 < 8x

Lastly, you divide by 8 in order to cancel out 8x solve for x. Since 8 is not a negative number, you DO NOT flip the sign.

\frac{-16}{8} < \frac{8x}{8}

-2 < x

3 0
3 years ago
Quadratic and Ratios...​
lozanna [386]

Answer:

x=0

Step-by-step explanation:

in the quadratic formula to only have one solution

b^{2} -4ac=0 for ax^2+bx+c=0

so we have

ax^2+b=c

ax^2+(b-c)=0

if we insert in the formula we have

0^2-4(a)(b-c)=0\\\\-4ab+4ac=0\\\\4ac=4ab\\\\\frac{4ac}{4a} = \frac{4ab}{4a}\\\\c=b

ax^2+b=c\\\\ax^2=b-b\\\\ax^2=0 since a≠0

\frac{ax^2}{a}=\frac{0}{a}  \\\\x^2=0\\\\x=0

8 0
3 years ago
I need help with both
NikAS [45]
1) 3 cm.
               5cm*8cm*3cm= 120cm^2
2) Rectangle

4 0
3 years ago
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