As stated the area of the circle is 85π ft2. The area of the sector BAC is a portion of this full circle area. the sector is made of 2 radii and arc that has rotated by 36°.
the magnitude of the central angle in the circle is 360°
Area for 360° central angle - 85π ft2
then the area for 1° = 85π ft2/360°
the area of 36° sector = 85π ft2/360° x 36°
= 8.5π ft2
Answer:
proportional because you can divide 16 and 36 by four and get 4/9
Answer:
a) 90 stamps
b) 108 stamps
c) 333 stamps
Step-by-step explanation:
Whenever you have ratios, just treat them like you would a fraction! For example, a ratio of 1:2 can also look like 1/2!
In this context, you have a ratio of 1:1.5 that represents the ratio of Canadian stamps to stamps from the rest of the world. You can set up two fractions and set them equal to each other in order to solve for the unknown number of Canadian stamps. 1/1.5 is representative of Canada/rest of world. So is x/135, because you are solving for the actual number of Canadian stamps and you already know how many stamps you have from the rest of the world. Set 1/1.5 equal to x/135, and solve for x by cross multiplying. You'll end up with 90.
Solve using the same method for the US! This will look like 1.2/1.5 = x/135. Solve for x, and get 108!
Now, simply add all your stamps together: 90 + 108 + 135. This gets you a total of 333 stamps!
Associative property of <span>multiplication</span>
Because of the symmetry, we can just go from x=0 to x=2 to find the area between
<span>y = x^2 and y = 4 </span>
<span>that area = ∫4-x^2 dx from 0 to 2 </span>
<span>= [4x - (1/3)x^3] from 0 to 2 </span>
<span>= 8 - 8/3 - 0 </span>
<span>= 16/3 </span>
<span>so when y = b </span>
<span>x= √b </span>
<span>and we have the area as </span>
<span>∫(b - x^2) dx from 0 to √b </span>
<span>= [b x - (1/3)x^3] from 0 to √b </span>
<span>= b√b - (1/3)b√b - 0 </span>
<span>(2/3)b√b = 8/3 </span>
<span>b√b =4 </span>
<span>square both sides </span>
<span>b^3 = 16 </span>
<span>b = 16^(1/3) = 2 cuberoot(2) </span>
<span>or appr 2.52</span>
