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alexgriva [62]
2 years ago
11

Part A. At the local baker you can get 10 cookies for $2. How many cookies could you get for $5 dollars?

Mathematics
1 answer:
Yakvenalex [24]2 years ago
7 0

Answer:

Pt. A: 25 cookies. Pt. B. $10.00

Step-by-step explanation:

1st you need to divide 10 cookies and $2 dollars, so 10/2= 5 cookies. So, it would be 5 cookies per dollar. So, then you would multiply 5 cookies*5 dollars, that equals 25. you would get 25 cookies for $5.00.  

So, for Part B, you would divide 50 cookies by $5 dollars, and that would equal $10.00.

Hope this helped you!!! (:

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What number is between 4 1/5 and 4.03
tatiyna

Answer:

I would say your right as 4 ⅕ would be 4.20.

3 0
2 years ago
The store allowed 85 people in 5 hours .. how many people were allowed to enter per hour?
ale4655 [162]

Answer:

17 people per hour

Step-by-step explanation:

85/5

3 0
3 years ago
5a+5b=25 and -5a+5b=35
Alex_Xolod [135]

add the two equations together

5a+5b=25

-5a+5b=35

------------------

 0  + 10b =60

divide by 10

b=6

5a + 5b = 25

5a +5(6) = 25

5a +30 =25

subtract 30 from each side

5a =-5

divide by 5

a = -1

Answer (-1,6)

or a=-1 b=6

3 0
3 years ago
One day, eleven babies are born at a hospital. Assuming each baby has an equal chance of being a boy or girl, what is the probab
Andrews [41]
You only need to consider the situations where 10 or 11 of the babies are girls, then subtract those probabilities from 1.  This will give probability that any other number up to 9 of the babies are girls.

Use binomial theorem.
P(x=k) = (nCk) p^k (1-p)^{n-k}

n = 11
k = 10,11
p = 1/2

P(x=10) = 11 (\frac{1}{2})^{11} = \frac{11}{2048} \\  \\ P(x=11) = 1(\frac{1}{2})^{11} = \frac{1}{2048} \\  \\ P(x \leq 9) = 1 - \frac{11}{2048} - \frac{1}{2048} \\  \\ P(x \leq 9)=\frac{2036}{2048} = \frac{509}{512}
4 0
3 years ago
The admissions office of a private university released the following admission data for the preceding academic year: From a pool
lina2011 [118]

Answer: Our required probability is 0.1695.

Step-by-step explanation:

Since we have given that

Number of male applicants = 4200

Number of female applicants = 3800

So, total number of applicants = 4200+3800 = 8000

Probability of male entered and subsequently enrolled is given by

0.4\times 0.4=0.16

Probability of female entered and subsequently enrolled is given by

0.4\times 0.45\\\\=0.18

Number of male entered and subsequently enrolled is given by

0.16\times 4200\\\\=672

Number of female entered and subsequently enrolled is given by

0.18\times 3800\\\\=684

So, Probability that a student who applied  for admission will be accepted by the university and subsequently will enroll is given by

\dfrac{672+684}{8000}\\\\=\dfrac{1356}{8000}\\\\=0.1695

Hence, our required probability is 0.1695.

3 0
3 years ago
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