Answer:
(3/4) -(1/4)i
Step-by-step explanation:
Your answer is correct.
one week she had 38 coins, all of them dimes and quarters. when she added them up, she had a total of 6.95, how many dimes did s
2 answers:
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Part A:
Given that lie <span>detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.
The case that the lie detector correctly determined that a selected person is saying the truth has a probability of 0.85
Thus p = 0.85
Thus, the probability that </span>the lie detector will conclude that all 15 are telling the truth if <span>all 15 applicants tell the truth is given by:
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</span>Part B:
Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.
The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.25
Thus p = 0.15
Thus, the probability that the lie detector will conclude that at least 1 is lying if all 15 applicants tell the truth is given by:
Part C:
Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.
The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.15
Thus p = 0.15
The mean is given by:
Part D:
Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.
The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.15
Thus p = 0.15
The <span>probability that the number of truthful applicants classified as liars is greater than the mean is given by:
</span>![P(X\ \textgreater \ \mu)=P(X\ \textgreater \ 1.9125) \\ \\ 1-[P(0)+P(1)]](https://tex.z-dn.net/?f=P%28X%5C%20%5Ctextgreater%20%5C%20%5Cmu%29%3DP%28X%5C%20%5Ctextgreater%20%5C%201.9125%29%20%5C%5C%20%20%5C%5C%201-%5BP%280%29%2BP%281%29%5D)
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Given that lie <span>detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.
The case that the lie detector correctly determined that a selected person is saying the truth has a probability of 0.85
Thus p = 0.85
Thus, the probability that </span>the lie detector will conclude that all 15 are telling the truth if <span>all 15 applicants tell the truth is given by:
</span>
<span>
</span>Part B:
Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.
The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.25
Thus p = 0.15
Thus, the probability that the lie detector will conclude that at least 1 is lying if all 15 applicants tell the truth is given by:
Part C:
Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.
The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.15
Thus p = 0.15
The mean is given by:
Part D:
Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.
The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.15
Thus p = 0.15
The <span>probability that the number of truthful applicants classified as liars is greater than the mean is given by:
</span>
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</span>
La edad de cada uno de los integrantes del acertijo es:
- <u>Luisa = 3 años </u>
- <u>Juan = 6 años </u>
- <u>Carmen = 8 años</u>
<em>Cálculo por medio de ecuaciones y el </em><em>método de igualación</em>.
Haciendo uso de la información brindada en el ejercicio, se procede a formular variables con las cuales se calcularán las ecuaciones, por lo tanto:
- <em>X = Edad de Luisa</em>
- <em>Y = Edad de Juan</em>
- <em>Z = Edad de Carmen</em>
Con el enunciado: <em>"Luisa es 3 años más joven que su hermano Juan"</em> se crea la primera ecuación:
- 1. Y = X + 3
Con el enunciado: <em>"Su hermana Carmen es 2 años mayor que Juan"</em>, se crea la segunda ecuación:
- 2. Z = Y + 2
Y con el enunciado: <em>"Juan tiene el doble de edad que Luisa"</em>, se crea la tercera ecuación:
- 3. X =
Ahora, utilizando el método de igualación, se reemplaza la <em>tercera ecuación en la primera</em>:
- Y = X + 3
- Y = (
) + 3
Y se procede a sumar:
- Y = (
- Y =
El dividendo se pasa al otro lado de la igualdad a multiplicar:
- 2Y = Y + 6
Y la variable "Y" que está sumando, se pasa al otro lado de la igualdad a restar:
- 2Y - Y = 6
- <u>Y = 6</u>
Con el valor de Y (edad de Juan) <em>se calcula X con la tercera ecuación</em>:
- X =
- X =
- <u>X = 3</u>
Una vez calculado el valor de X (edad de Luisa), se procede a <em>calcular el valor de Z con la segunda ecuación</em>:
- Z = Y + 2
- Z = 6 + 2
- <u>Z = 8</u>
Por lo tanto, se calcula que <u>la edad de Luisa es 3 años, la edad de Juan es 6 años y la edad de Carmen es 8 años</u>.
Más información sobre ecuaciones: