Jacob wants to build a rectangular enclosure for his animals. One side of the pen will be against the barn,so he needs no fence on that side.
Let w be the width of the enclosure (perpendicular to the barn) and let l be the length of the enclosure (parallel to the barn).
one side of the length is not counted for perimeter because one side of length will be against the barn.
Perimeter = 400 ft
Perimeter of rectangle = L + W + W
400 = L + 2W
L = 400 - 2W
Area = L * W
Replace L by 400 - 2W
A(W) = (400 - 2W) * W
Now we find out x coordinate of vertex to find the width that maximize the area
a= -2 and b = 400
The width w would maximize the area is w = 100ft
To find maximum area we plug in 100 for W in A(W)
the maximum area is 20,000 square feet
Answer:
136 m2 Option c
Step-by-step explanation:
136 m2
1 base = 6 × 7 = 42
2 sides = 2(7 × 5) = 70
2 triangles = 2(6 × 4
2
) = 24
SA = 42 + 70 + 24 = 136 m2
Answer:
Total surface area of the given figure is 246.75 square mile.
Step-by-step explanation:
Surface Area of the given figure = Lateral surface area + Area of the base
Lateral surface area of the figure = Sum of the areas of 5 triangular surfaces
= 
= 
= 162.75 mi²
Surface area of the pentagonal base = 84 mi²
Total surface area of the figure = 162.75 + 84
= 246.75 mi²
Therefore, total surface area of the given figure is 246.75 square mile.
Let there be 2x science and 5x art books
<span>science books sold = 2x × 0.2 = 0.4x </span>
<span>science books unsold = 2x – 0.4x = 1.6x </span>
<span>art books sold = 5x × 0.2 = x </span>
<span>art books unsold = 5x – x = 4x </span>
<span>total books unsold = 1.6x + 4x = 5.6x </span>
<span>5.6x = 2240 </span>
<span>x = 400 </span>
<span>2x science = 800 </span>
<span>and 5x art books = 2000 </span>
Answer:
20 Outcomes.
Step-by-step explanation:
A-1 A-2 A-3 A-4
B-1 B-2 B-3 B-4
C-1 C-2 C-3 C-4
D-1 D-2 D-3 D-4
E-1 E-2 E-3 E-4
Hope this helps!
