How to write 3,000,000+600,000+80,000+10 in written form

Mathematics

2 answers:

solong [7]3 years ago

7 0

Three million plus six hundred thousand plus eighty thousand plus ten. Did i help?

zavuch27 [327]3 years ago

6 0

Written form is just how you would usually see a number. So it would be 3,680,010.

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--Multiplying Polynomials--Use the given formulas to express the volume of each object as a polynomial.

sasho [114]

32.

V = L*w*h

Where:

V= Volume

L= Length = x+5

w= width = x-2

h= height = 6

Replacing with the values given:

V= (x+5) * (x-2) * 6

V =[ (x*x) + (x*-2) + (5*X) +5*-2) ] * 6

V= [ x^2 - 2x + 5x - 10 ] * 6

V= [ x^2 + 3x - 10] *6

V= (x^2*6) + (3x*6)+ ( - 10 * 6)

V= 6x^2 + 18x - 60

6 0

1 year ago

I need help with this question it's really hardd

Vsevolod [243]

1st one on second row I think

7 0

3 years ago

Suppose that you have $6000 to invest. Which investment yields the greater return over four years: 8.25% compounded quarterly or

WARRIOR [948]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.25\%\to \frac{8.25}{100}\to &0.0825\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.0825}{4}\right)^{4\cdot 4}\implies A=6000(1.020625)^{16}\\\\
-------------------------------\\\\$

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.3\%\to \frac{8.3}{100}\to &0.083\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semiannually, thus two}
\end{array}\to &2\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.083}{2}\right)^{2\cdot 4}\implies A=6000(1.0415)^8$

compare them away.

4 0

3 years ago

In trapezoid ABCD, AC is a diagonal and ∠ABC≅∠ACD. Find AC if the lengths of the bases BC and AD are 12m and 27m respectively.

xz_007 [3.2K]

Answer:

Length of diagonal is 18 m

Step-by-step explanation:

Given in trapezoid ABCD. AC is a diagonal and ∠ABC≅∠ACD. The lengths of the bases BC and AD are 12m and 27m. We have to find the length of AC.

Let the length of diagonal be x m

In ΔABC and ΔACD

∠ABC=∠ACD (∵Given)

∠ACB=∠CAD (∵Alternate angles)