A. 0.15 Because its making me type twenty characters.
25% of 64 is 16
![\frac{25}{100} = \frac{x}{64} \\ x = \frac{64 \times 25}{100} = \frac{1600}{100} = 16](https://tex.z-dn.net/?f=%20%5Cfrac%7B25%7D%7B100%7D%20%20%3D%20%20%5Cfrac%7Bx%7D%7B64%7D%20%20%5C%5C%20x%20%3D%20%20%5Cfrac%7B64%20%5Ctimes%2025%7D%7B100%7D%20%20%3D%20%20%5Cfrac%7B1600%7D%7B100%7D%20%20%3D%2016)
it will work properly 16 times
![64 - 16 = 48](https://tex.z-dn.net/?f=64%20-%2016%20%3D%2048)
it will not work 48 times
hope this helps
Did you get the answer me and you need help and no one dont want to help i hope you found the answer because i really need it math is very hard.
Answer:
what are the answer choices post it on the comments
Step-by-step explanation:
Answer:
![R=\frac{QJ}{I^2t}](https://tex.z-dn.net/?f=R%3D%5Cfrac%7BQJ%7D%7BI%5E2t%7D)
Step-by-step explanation:
So we have the equation:
![Q=\frac{I^2Rt}{J}](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7BI%5E2Rt%7D%7BJ%7D)
And we want to solve for R.
First, let's multiply both sides by J to remove the fraction on the right. So:
![(J)Q=(J)\frac{I^2Rt}{J}](https://tex.z-dn.net/?f=%28J%29Q%3D%28J%29%5Cfrac%7BI%5E2Rt%7D%7BJ%7D)
Simplify the right:
![JQ=I^2Rt](https://tex.z-dn.net/?f=JQ%3DI%5E2Rt)
We can rewrite our equation as:
![JQ=R(I^2t)](https://tex.z-dn.net/?f=JQ%3DR%28I%5E2t%29)
So, to isolate the R variable, divide both sides by I²t:
![\frac{JQ}{I^2t}=\frac{R(I^2t)}{I^2t}](https://tex.z-dn.net/?f=%5Cfrac%7BJQ%7D%7BI%5E2t%7D%3D%5Cfrac%7BR%28I%5E2t%29%7D%7BI%5E2t%7D)
The right side cancels, so:
![R=\frac{QJ}{I^2t}](https://tex.z-dn.net/?f=R%3D%5Cfrac%7BQJ%7D%7BI%5E2t%7D)
And we are done!