32.
V = L*w*h
Where:
V= Volume
L= Length = x+5
w= width = x-2
h= height = 6
Replacing with the values given:
V= (x+5) * (x-2) * 6
V =[ (x*x) + (x*-2) + (5*X) +5*-2) ] * 6
V= [ x^2 - 2x + 5x - 10 ] * 6
V= [ x^2 + 3x - 10] *6
V= (x^2*6) + (3x*6)+ ( - 10 * 6)
V= 6x^2 + 18x - 60
1st one on second row I think
Answer:
Length of diagonal is 18 m
Step-by-step explanation:
Given in trapezoid ABCD. AC is a diagonal and ∠ABC≅∠ACD. The lengths of the bases BC and AD are 12m and 27m. We have to find the length of AC.
Let the length of diagonal be x m
In ΔABC and ΔACD
∠ABC=∠ACD (∵Given)
∠ACB=∠CAD (∵Alternate angles)
By AA similarity theorem, ΔABC~ΔACD
∴ their corresponding sides are proportional

Comparing first two, we get
⇒ 
⇒ 
⇒ 
hence, the length of diagonal is 18 m