Answer:
4√2 and 5+4√2
Step-by-step explanation:
Let the two numbers be x ad y
Smaller = y
Bigger = x
If a positive real number is 5 more than another, then;
x = 5 + y ... 1
When - 10 times the smaller is added to the square of the larger, the result is 57, then;
-10y + x² = 57 ...2
Substitute 1 into 2;
-10y + (5+y)² = 57
-10y + 25+10y+y² = 57
y²+25 = 57
y² = 57 - 25
y² = 32
y = √32
y = 4√2
Since x = 5 + y
x = 5 + 4√2
Hence rhe numbers are 4√2 and 5+4√2
Replace f(x) with 0 and swith the equation around to solve for x
x^4 - 32x^2 - 144 = 0
Factor the left side:
(x+6) (x-6) (x^2+4)
so far we have x+6 = 0, x = -6
x -6 = 0, x = 6
solve x^2 +4 = 0
x^2 = -4
x = sqrt(-4)
x = 2i, -21
The answer is B) 2i, 6, -6
Answer:
The answer to your question is: 12
Step-by-step explanation:
You have a function with two conditions,
- the first condition do not consider number nine, because it uses the symbol <, then we can not evaluate nine in this function.
- the second condition considers nine because uses the symbol ≤ which means that nine is considered here, but the function equals 12, so that is the solution.
Answer:
1) 8 2) -33/9
Step-by-step explanation:
1) (1/2)x = -1/2 + 9/2
(1/2)x = 4 x = 8
2) distributing 3/2, 9x/2 - 15/2 = -24
9x/2 = -24 + 15/2
9x/2 = -33/2
9x = -66/2
9x = -33
x = -33/9
