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2 years ago

Help please . . . .

Mathematics

1 answer:

Travka [436]2 years ago

3 0

Answer:

Your answer is A.

Step-by-step explanation:

Looking at the graphing two-equation: y = x^3 -3 and y = x^2+6 are up there, it can help us determine the limit of domain.

The dot is the x<=2 for equation y=x^3-3.

The circle is x>2 for equation y=x^2+6

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Find an equation of the tangent to the curve x =5+lnt, y=t2+5 at the point (5,6) by both eliminating the parameter and without e

svet-max [94.6K]

ANSWER

$y = 2x -4$

EXPLANATION

Part a)

Eliminating the parameter:

The parametric equation is

$x = 5 + ln(t)$

$y = {t}^{2} + 5$

From the first equation we make t the subject to get;

$x - 5 = ln(t)$

$t = {e}^{x - 5}$

We put it into the second equation.

$y = { ({e}^{x - 5}) }^{2} + 5$

$y = { ({e}^{2(x - 5)}) } + 5$

We differentiate to get;

$\frac{dy}{dx} = 2 {e}^{2(x - 5)}$

At x=5,

$\frac{dy}{dx} = 2 {e}^{2(5 - 5)}$

$\frac{dy}{dx} = 2 {e}^{0} = 2$

The slope of the tangent is 2.

The equation of the tangent through

(5,6) is given by

$y-y_1=m(x-x_1)$

$y - 6 = 2(x - 5)$

$y = 2x - 10 + 6$

$y = 2x -4$

Without eliminating the parameter,

$\frac{dy}{dx} = \frac{ \frac{dy}{dt} }{ \frac{dx}{dt} }$

$\frac{dy}{dx} = \frac{ 2t}{ \frac{1}{t} }$

$\frac{dy}{dx} = 2 {t}^{2}$

At x=5,

$5 = 5 + ln(t)$

$ln(t) = 0$

$t = {e}^{0} = 1$

This implies that,

$\frac{dy}{dx} = 2 {(1)}^{2} = 2$

The slope of the tangent is 2.

The equation of the tangent through

(5,6) is given by

$y-y_1=m(x-x_1)$

$y - 6 = 2(x - 5) =$

$y = 2x -4$

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3 years ago

Natasha wants to find out if the neighborhood supports lowering the speed limit on the street in front of her school. Which is a

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The answer is
Thirty residents who live within a 2 mile radius of natashas school.

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2 years ago

two circles are externally tangent to each other. One circle has a diameter of 62 yards and the distance between the centers of

maksim [4K]

Answer:

108 yards

Step-by-step explanation:

Let circle A be the circle with the 62 yard diameter

Let circle B be the circle whose diameter we are trying to solve for.

Externally tangent circles are circles which touch each other and share a common external tangent.
Circle A has a tangent of 62 yards and thus a radius ( half the diameter) of 31 yards.
The distance between the centers of the 2 circles is 85 yards. If you subtract the radius ( distance from the center of the circle to its circumference) of circle A then we'll only be left with the radius of circle B.
85 - 31= 54 yards which is the radius of circle B
To get the diameter: 54 x 2 = 108 yards