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Natasha_Volkova [10]

3 years ago

13

What is the area of the trapezoid shown below?

2 answers:

jekas [21]3 years ago

6 0

24....................i think I'm sorry if it's wrong

kicyunya [14]3 years ago

3 0

Answer:

Step-by-step explanation:

idk

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-53 + n = -28 solve for n

frozen [14]

Answer:

n will be equal 25

Step-by-step explanation:

-53 + n = -28

collect like terms, and we will have

n = -28 + 53

n = 25

5 0

3 years ago

Read 2 more answers

If you place a 20ft ladder 4ft from the base of the wall, what is the angle measure of the ladder to the ground to the nearest d

artcher [175]

Given:

Length of the ladder = 20 ft

Distance between base of the ladder and wall = 4 ft

To find:

The angle measure of the ladder to the ground to the nearest degree.

Solution:

Ladder is the hypotenuse of a right triangle. Here, we have,

Hypotenuse = 20 ft

Base = 4 ft

In a right angle triangle,

$\cos \theta=\dfrac{Base}{Hypotenuse}$

$\cos \theta=\dfrac{4}{20}$

$\cos \theta=\dfrac{1}{5}$

Taking cos inverse on both sides, we get

$\theta=\cos^{-1}\dfrac{1}{5}$

$\theta=78.46304^\circ$

$\theta\approx 78^\circ$

Therefore, the correct option is A.

8 0

3 years ago

1. Order the numbers from least to greatest. 66 V21, 5.38 3

IrinaK [193]

Answer:

3, 5.38, 66, V21

Step-by-step explanation:

I assumed that V was the roman numeral V, which is equivalent to the number 5. I then multiplied 5 by 21 which is 105. If this is not the case and they simply wanted us to replace the v with a 5, then the answer would still be correct because 521 is greater than all the numbers in this set. Hope this helps.

7 0

3 years ago

A 15-ft ladder leans against a wall. The lower end of the ladder is being pulled away from the wall at the rate of 1.5 ft/sec. L

Aleks [24]

Answer:

The top of the ladder is sliding down at a rate of 2 feet per second.

Step-by-step explanation:

Refer the image for the diagram. Consider $\Delta ABC$ as right angle triangle. Values of length of one side and hypotenuse is given. Value of another side is not known. So applying Pythagoras theorem,

$\left ( AB \right )^{2}+\left ( BC \right )^{2}=\left ( AC \right )^{2}$

From the given data, $L=15\:ft=AC$ , $y=9\:ft=AB$ and $x=BC$

Substituting the values,

$\therefore \left ( 9 \right )^{2}+\left ( x \right )^{2}=\left ( 15 \right )^{2}$

$\therefore 81+x^{2}=225$

$\therefore x^{2}=225-81$

$\therefore x^{2}=144$

$\therefore \sqrt{x^{2}}=\sqrt{144}$

$\therefore x=\pm 12$

Since length can never be negative, so $x= 12$ .

Now to calculate $\dfrac{dy}{dt}$ again consider following equation,

$\left ( y \right )^{2}+\left ( x \right )^{2}=\left ( l \right )^{2}$

Differentiate both sides of the equation with respect to t,

$\dfrac{d}{dt}\left(y^2+x^2\right)=\dfrac{d}{dt}\left(l^2\right)$

Applying sum rule of derivative,

$\dfrac{d}{dt}\left(y^2\right)+\dfrac{d}{dt}\left(x^2\right)=\dfrac{d}{dt}\left(l^2\right)$

$\dfrac{d}{dt}\left(y^2\right)+\dfrac{d}{dt}\left(x^2\right)=\dfrac{d}{dt}\left(225\right)$

Applying power rule of derivative,

$2y\dfrac{dy}{dt}+2x\dfrac{dx}{dt}=0$

Simplifying,

$y\dfrac{dy}{dt}+x\dfrac{dx}{dt}=0$

Substituting the values,

$9\dfrac{dy}{dt}+12\times1.5=0$

$9\dfrac{dy}{dt}+18=0$

Subtracting both sides by 18,

$9\dfrac{dy}{dt}=-18$

Dividing both sides by 9,

$\dfrac{dy}{dt}= - 2$

Here, negative indicates that the ladder is sliding in downward direction.

$\therefore \dfrac{dy}{dt}= 2\:\dfrac{ft}{sec}$

7 0

3 years ago

The ratio of footballs to total pieces of equipment is... and we have 2 baseballs and 6 footballs

kirza4 [7]

Answer:

1:3 ............... ......

3 0

3 years ago