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2 years ago

Find dy/dx of y = sin inverse ( x - 1 ).

Mathematics

1 answer:

jolli1 [7]2 years ago

8 0

$\frac{1}{ \sqrt{1 - {(x - 1)}^{2} } }$

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What else would need to be congruent to show that triangle ABC equals triangle DEF by AAS

timofeeve [1]

Answer:

Olha,pirmieiro voce adiciona o AAS com o AABC e depois divide por 2. depois, voce ai ter que simplificar. eu iria simplificar por 2 mas vcque sabe.

Step-by-step explanation:

8 0

2 years ago

Kristine is comparing the typing speeds of her friends. The following tables shows their typing speeds.

STALIN [3.7K]

Emma types the fastest

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3 years ago

Write an equation in slope intercept form for the line through the two points

Musya8 [376]

$m= \frac{y2-y1}{x2-x1} \\ \\ m= \frac{-2-2}{2-(-2)} \\ \\ m= \frac{-4}{4} \\ \\ m=-1$

$y=mx+b \\ \\ y=-1x+b$

$(2)=(-1)(-2)+b \\ \\ 2=2+b \\ \\ 0=b$

$y=-1x+0 \\ \\ y=-x$

5 0

2 years ago

2, -6, 18, __, 162, __, ...

Semmy [17]

Answer:

-54, 162, -486

Step-by-step explanation:

You multiply the number in front by -3.

2*-3=-6

-6*-3=18

18*-3=-54

-54*-3=162

162*-3=-486

-Please mark as brainliest!-

-Hope this helps!-

-Good Luck!-

7 0

3 years ago

Can you guys help me out on this? I'm still learning sign, cosign, and tangent :)

Yakvenalex [24]

Answer:

$\sin d = \frac{4}{7}$ ; $\sin e = \frac{\sqrt{33} }{7}$

$\cos d = \frac{\sqrt{33} }{7}$ ; $\cos e = \frac{4}{7}$

$\tan d = \frac{4}{\sqrt{33} }$ ; $\tan e = \frac{\sqrt{33} }{4}$

Step-by-step explanation:

For a right angled triangle with one of its angle α (alpha) :-

$\sin \alpha = \frac{Side \: opposite \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}$

$\cos \alpha = \frac{Side \: adjacent \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}$

$\tan \alpha = \frac{Side \: opposite \: to \: \alpha }{Side \: adjacent \: to \: \alpha }$

__________________________________________________

According to the question ,

1) When α (alpha) = d

$\sin d = \frac{4}{7}$

$\cos d = \frac{\sqrt{33} }{7}$

$\tan d = \frac{4}{\sqrt{33} }$

2) When α (alpha) = e

$\sin e = \frac{\sqrt{33} }{7}$

$\cos e = \frac{4}{7}$

$\tan e = \frac{\sqrt{33} }{4}$

3 0

2 years ago