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3 years ago

7

Evaluate the function ,when D = {9, 15, 30}.

2 answers:

Anna [14]3 years ago

6 0

The answer is R={6, 10, 20}

asambeis [7]3 years ago

4 0

unable to evaluate the triangle

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Convert the following repeating Decimals to fractions

arsen [322]

Step-by-step explanation:

1. 0.030303......*100

=3.0303....

$3.0303..... - 0.030303.... = 3$

$\frac{99 \times 0.030303}{99} = \frac{3}{99}$

$0.030303 = \frac{1}{33}$

<h3>This is the explination</h3>

2.

$= \frac{1}{3}$

4 0

2 years ago

Use the Taylor series you just found for sinc(x) to find the Taylor series for f(x) = (integral from 0 to x) of sinc(t)dt based

Marina CMI [18]

In this question (brainly.com/question/12792658) I derived the Taylor series for $\mathrm{sinc}\,x$ about $x=0$ :

$\mathrm{sinc}\,x=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}$

Then the Taylor series for

$f(x)=\displaystyle\int_0^x\mathrm{sinc}\,t\,\mathrm dt$

is obtained by integrating the series above:

$f(x)=\displaystyle\int\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}\,\mathrm dx=C+\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

We have $f(0)=0$ , so $C=0$ and so

$f(x)=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

which converges by the ratio test if the following limit is less than 1:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(-1)^{n+1}x^{2n+3}}{(2n+3)^2(2n+2)!}}{\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}}\right|=|x^2|\lim_{n\to\infty}\frac{(2n+1)^2(2n)!}{(2n+3)^2(2n+2)!}$

Like in the linked problem, the limit is 0 so the series for $f(x)$ converges everywhere.

7 0

3 years ago

Hello people can you please help me on this

snow_lady [41]

Step-by-step explanation:

<u>Step 1: Complete the first equation</u>

0.1 is a tenth, therefore if we have 15.3 then we have 153 tenths.

Step 2: Complete the second equation

15.3 / 3 = 5.1

0.1 is a tenth, therefore if we have 5.1 then we have 51 tenths.

<u>Step 3: Complete the third equation</u>

15.3 / 3 = 5.1

6 0

3 years ago

AB and BC form a right angle at point B if A = (-3,-1) and B = (4,4) what is the equation if BC

sergejj [24]

Answer:

$7x+5y-48=0$

Step-by-step explanation:

Refer the attached figure .

We are given a line AB

Point A $=(x_1,y_1) = (-3,-1)$

Point B $=(x_2,y_2) = (4,4)$

Formula for slope 'm' when two points are given :

$m=\frac{y_2-y_1}{x_2-x_1}$

Substituting thew values

$m=\frac{4-(-1)}{4-(-3)}$

$m=\frac{5}{7}$

Since we are given that AB is perpendicular to BC

So, By property - perpendicular slopes are negative reciprocals of each other.

$\Rightarrow m_1\times m_2 =-1$

$\Rightarrow \frac{5}{7}\times m_2 =-1$

$\Rightarrow m_2 = \frac{-7}{5}$

So, Slope for line BC : $m_2 = \frac{-7}{5}$

Point B = (4,4)

Formula of equation of line : $y-y_1=m(x-x_1)$

$y-4=\frac{-7}{5}(x-4)$

$5(y-4)=-7(x-4)$

$5y-20=-7x+28$

$7x+5y-20-28=0$

$7x+5y-48=0$

Hence the equation of line BC : $7x+5y-48=0$

5 0

3 years ago

22. You bought a CD for $16.95 and eight blank videotapes.

aleksandrvk [35]

Answer:

t=4.45

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers