Let x = # of tickets sold in advance
Let y = # of tickets sold the day of
Cost of the tickets & total sales: 6x & 10y = 6828
You also know y = x + 206
Take the equation mentioned above y = x + 206 and sub it in anywhere the variable y is in the other equations so you'll have this:
6x + 10(x+206) = 6828
Now solve for x to get x = 298
To finish the problem, you must now find the number of y tickets sold.
Sub your x value that you found back into the equation y = x + 206 and you'll get y = 504.
So, 298 tickets were sold in advance and 504 tickets were sold the day of
I think the answer is -7x(-7)x(-7)
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Answer:
a) 3
b) 4
Step-by-step explanation:
The point P is(3,4)
which means that 3 is the point P's x- coordinate and 4 is it's y-coordinate
Because we use the axes as our reference point when plotting points,
the distance of P from x-axis and y-axis would be the point itself.
F is the answer lol BTW it's f
