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inessss [21]
3 years ago
10

Given the Arithmetic sequence A1,A2,A3,A4 28, 33, 38, 43 What is the value of A11?

Mathematics
2 answers:
denis-greek [22]3 years ago
8 0
Solutions 

We are given<span> the Arithmetic sequence -
A1,A2,A3,A4
</span>28,33,38,43

As we know the common difference can be found by subtracting the first term from the second term. 

33 - 28 = 5 ((the common difference (d) = 5))

an = a1 + (n - 1) * d

The variable n = the term you want to find which is = 11

a1 = 1 term = 28

d = difference = 5

Subtraction 

a11 = 28 + (11 - 1) * 5&#10;&#10;a11 = 28 + 10 * 5&#10;&#10;a11 = 28 + 50&#10;&#10;a11 = 78
harkovskaia [24]3 years ago
7 0
28,33,38,43

the common difference can be found by subtracting the first term from the second term.....33 - 28 = 5....so the common difference (d) = 5

an = a1 + (n - 1) * d
n = the term u want to find = 11
a1 = first term = 28
d = common difference = 5
now we sub
a11 = 28 + (11 - 1) * 5
a11 = 28 + 10 * 5
a11 = 28 + 50
a11 = 78
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Step-by-step explanation:

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3 years ago
If cos Θ = negative 4 over 7, what are the values of sin Θ and tan Θ? sin Θ = ±square root 33 over 7; tan Θ = ±square root 33 ov
Natali5045456 [20]

Answer:

Answer = Option A;

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Remove the negative sign and evaluate cosθ = 4/7

cosθ = adjacent/hypotenuse.

Please see attached image for the right-angle triangle representation.

Let opp = length of opposite side of the triangle.

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Using Pythagoras theorem,

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6 0
3 years ago
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arlik [135]

Answer:

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Step-by-step explanation:

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6 0
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