The coefficient of the second term in the expansion of the binomial (4x+3y) to the 3rd power
1 answer:
You can solve this easily by using Pascal's Triangle (look that up if need be).
Here are the first four rows of P. Triangle:
1
1 1
1 2 1
1 3 3 1
example: expand (a+b)^3.
Look at the 4th row. Borrow and use those coefficients:
1a^3 + 3 a^2b + 3ab^2 + b^3
Now expand (4x+3y)^3:
1(4x)^3 + 3(4x)^2(3y) + 3(4x)*(3y)^2 + (3y)^3
Look at the 2nd term (above):
3(4x)^2(3y) can be re-written as 144x^2y.
The coeff of the 2nd term is 144. Note that (4)^2 = 16
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$320 if your saying how much in all its basically 8 times 4 add a zero to the end
Step-by-step explanation:
Answer:
a) -3x -2y = 12
b) 10x = -15y + 60
c) 6x +9y = 18
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y= -96 is the answer to the problem
No the answer is -13. Please mark me brainliest!