1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
natali 33 [55]
3 years ago
9

What is the measure of the angle x?​

Mathematics
1 answer:
navik [9.2K]3 years ago
4 0
AOB = 2 . x
2x = 60°
x = 30°
You might be interested in
What is the slope if the form is y=-x-6
Irina-Kira [14]

The slope will be -1

4 0
2 years ago
Read 2 more answers
The boundary of a lamina consists of the semicircles y = 1 − x2 and y = 16 − x2 together with the portions of the x-axis that jo
oksano4ka [1.4K]

Answer:

Required center of mass (\bar{x},\bar{y})=(\frac{2}{\pi},0)

Step-by-step explanation:

Given semcircles are,

y=\sqrt{1-x^2}, y=\sqrt{16-x^2} whose radious are 1 and 4 respectively.

To find center of mass, (\bar{x},\bar{y}), let density at any point is \rho and distance from the origin is r be such that,

\rho=\frac{k}{r} where k is a constant.

Mass of the lamina=m=\int\int_{D}\rho dA where A is the total region and D is curves.

then,

m=\int\int_{D}\rho dA=\int_{0}^{\pi}\int_{1}^{4}\frac{k}{r}rdrd\theta=k\int_{}^{}(4-1)d\theta=3\pi k

  • Now, x-coordinate of center of mass is \bar{y}=\frac{M_x}{m}. in polar coordinate y=r\sin\theta

\therefore M_x=\int_{0}^{\pi}\int_{1}^{4}x\rho(x,y)dA

=\int_{0}^{\pi}\int_{1}^{4}\frac{k}{r}(r)\sin\theta)rdrd\theta

=k\int_{0}^{\pi}\int_{1}^{4}r\sin\thetadrd\theta

=3k\int_{0}^{\pi}\sin\theta d\theta

=3k\big[-\cos\theta\big]_{0}^{\pi}

=3k\big[-\cos\pi+\cos 0\big]

=6k

Then, \bar{y}=\frac{M_x}{m}=\frac{2}{\pi}

  • y-coordinate of center of mass is \bar{x}=\frac{M_y}{m}. in polar coordinate x=r\cos\theta

\therefore M_y=\int_{0}^{\pi}\int_{1}^{4}x\rho(x,y)dA

=\int_{0}^{\pi}\int_{1}^{4}\frac{k}{r}(r)\cos\theta)rdrd\theta

=k\int_{0}^{\pi}\int_{1}^{4}r\cos\theta drd\theta

=3k\int_{0}^{\pi}\cos\theta d\theta

=3k\big[\sin\theta\big]_{0}^{\pi}

=3k\big[\sin\pi-\sin 0\big]

=0

Then, \bar{x}=\frac{M_y}{m}=0

Hence center of mass (\bar{x},\bar{y})=(\frac{2}{\pi},0)

3 0
3 years ago
What is the slope of the line?
Ede4ka [16]

Answer:

-1

Step-by-step explanation:

Remember, slope is rise/run

Start from a point on the line and count up and over until you reach another point on the line.

For example, start from (0,-2), count up and left until you get to (-2,0). This gets you 2/2, which reduces to 1.

Since the line represents a negative slope, the slope is -1.

7 0
3 years ago
Simplify. Assume that all variables are positive.
Alja [10]
I'm confused... Should there be more pictures? This in incomplete...
3 0
2 years ago
What is the total resistance of a parallel circuit that has two loads? Load one has a resistance of 10 ohms. Load two has a resi
Romashka-Z-Leto [24]

Answer:

The total resistance is 7.0588\Omega

Step-by-step explanation:

Attached please find the circuit diagram. The circuit is composed by a voltage source and two resistors connected in parallel: R_1=10\Omega and R_2=24\Omega.

First step: find the total current

For finding the current that the voltage source can provide, you must find the current consumed by each load and then add both. To do that, take first into account that the voltage is the same for both resistors (R_1 and R_2).

  • I_{R_1}=\frac{V_S}{R_1}
  • I_{R_2}=\frac{V_S}{R_2}

The total current is:

I_{TOTAL}=I_{R_1}+I_{R_2}=\frac{V_S}{R_1}+\frac{V_S}{R_2}=\frac{R_2\cdot V_S+R_1\cdot V_S}{R_1\cdot R_2}

I_{TOTAL}=V_S\cdot \frac{R_1+R_2}{R_1\cdot R_2}

Now, the total resistance (R_{TOTAL}) would be the voltage divided by the total current:

R_{TOTAL}=\frac{V_S}{I_{TOTAL}}

If you replace I_{TOTAL} by the expression obtained previously, the total resistance would be:

R_{TOTAL}=\frac{V_S}{V_S\cdot \frac{R_1+R_2}{R_1\cdot R_2}}

After simplifying the terms you should get:

R_{TOTAL}=\frac{R_1\cdot R_2}{R_1 + R_2}}

Now, you must replace the values of the resistors:

R_{TOTAL}=\frac{(10\Omega )\cdot (24\Omega)}{10\Omega + 24\Omega}}=\frac{120}{17}\Omega=7.0588\Omega

Thus, the total resistance is 7.0588\Omega

3 0
3 years ago
Other questions:
  • Solve these simultaneous equations Using the algerbraic method
    14·1 answer
  • Which of the following relations is a function?
    15·1 answer
  • Which graph shows the result of dilating this figure by a factor of 4 about the origin?
    12·2 answers
  • Which of the following is a possible value for X
    8·2 answers
  • Who ever answers ths is 52 minutes will get brainlyeiest
    5·2 answers
  • 5 is what percent of 250?
    14·1 answer
  • The local newspaper has letters to the editor from 10 people. If this number represents 4% of all of the newspaper's readers, ho
    13·1 answer
  • Write the equation of the line passing through the points (-4, 5) and (4, 1).
    6·1 answer
  • What is the coefficient of the term of degree 4 in this polynomial?<br> x^8+2x^4 - 4x^3 + x^2-1
    10·1 answer
  • The area formula for rectangular shapes is A=LW. What is the area of a rectangular shape with the dimensions of <img src="https:
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!