You use a system of equations to solve this.
x will be one integer and y will be the other.
2y - 7 = x
x^2 + y^2 = 433
You can plug (2y - 7) in for x in the second equation.
(2y - 7)^2 + y^2 = 433
4y^2 - 28y + 49 + y^2 = 433
5y^2 - 28y -384 = 0
y = 12 or -32/5
It has to be 12 since -32/5 is not an integer.
Plug 12 in for y to get x.
2(12) - 7 = x
x = 17
The integers are 12 and 17.
Answer:
A and C
Step-by-step explanation:
Let Triangle ABC is a right angle traingle.
From Option A
AB= 24, BC= 26 and AC=10
By Pythagorean Triplet
(AB)^2 + (AC)^2 = (24)^2 + (10)^2
= 576+100
(AB)^2 + (AC)^2 = 676 ---------------- (I)
(BC)^2 = 26^2 = 676 -------------------(ii)
From (I) and (ii)
(BC)^2 = (AB)^2 + (AC)^2
Therefore, the sides 10,24 and 26 are the sides of the right angle triangle.
From Option C
AB= 18, BC= 30 and AC=24
By Pythagorean Triplet
(AB)^2 + (AC)^2 = (18)^2 + (24)^2
= 324+576
(AB)^2 + (AC)^2 = 900---------------- (I)
(BC)^2 = 30^2 = 900 -------------------(ii)
From (I) and (ii)
(BC)^2 = (AB)^2 + (AC)^2
Therefore, the sides 18, 24 and 30 are the sides of the right angle triangle.
