1.) 4 - t = 3(t - 1) - 5
4 - t = 3t - 3 - 5
4 - t = 3t - 8
3t + t = 4 + 8
4t = 12
t = 12/4 = 3
2.) 8x - 2(x + 1) = 2(3x - 1)
8x - 2x - 2 = 6x - 2
6x - 2 = 6x - 2
0 = 0
solution is identity.
3.) 3(c - 2) = 2(c - 6)
3c - 6 = 2c - 12
3c - 2c = -12 + 6
c = -6
4.) 0.5(m + 4) = 3(m - 1)
0.5m + 2 = 3m - 3
3m - 0.5m = 2 + 3
2.5m = 5
m = 5/2.5 = 2
m = 2
Answer:
x = 5
Step-by-step explanation:
√(2x − 1) + 2 = x
√(2x − 1) = x − 2
2x − 1 = (x − 2)²
2x − 1 = x² − 4x + 4
0 = x² − 6x + 5
0 = (x − 1) (x − 5)
x = 1 or 5
Check for extraneous solutions.
√(2(1) − 1) + 2 = 1
√(1) + 2 = 1
3 = 1
No solution
√(2(5) − 1) + 2 = 5
√(9) + 2 = 5
5 = 5
x = 5
Answer:
-4
Step-by-step explanation:
(-2)^2=4 because a negative number squared is always positive
-(2)^2=-4
