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3 years ago

13

One slice of cheese pizza contains 290 calories. A medium-size orange has one-fifth that number of calories. How many calories a

re in a medium-size orange

2 answers:

Ierofanga [76]3 years ago

6 0

Do 1 divided by 5 and get .2 then do 290 divided by .2

brilliants [131]3 years ago

3 0

Multiply 290 by 1/5 to get your answer.

There are 58 calories in a medium size orange,

Hope this helped!

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Sophia's Diner sold 80 milkshakes last week. 90% of the milkshakes had whipped cream on top. How many milkshakes with whipped cr

Contact [7]

80 x 90/100 = 72

Therefore there were 72 milkshakes with whipped cream that were sold.

8 0

3 years ago

Read 2 more answers

Help ASAP please and explain

Y_Kistochka [10]

Answer:

37

Step-by-step explanation:

There are 2 ways to do this, the first is to just count the number of shaded squares (35)

The second is to find the area of the larger shaded square and subtract the smaller un-shaded rectangles

The large square is 7x7=49 squares

There are two 2x3 rectangles, which are 6 each

49-6-6=37

5 0

3 years ago

THIS IS REALLY IMPORTANT 7TH GRADE MATH:

Oksana_A [137]

Rectangle perimeter is 53 meters.

L = W + 2.3

To find the options of a perimeter, divide by 4.

= 13.25

So if this was a square, it would be 13.25 for both L and W but it's not.

Since the W has 2.3 meters more then the L, we do this.

13.25 + 2.3 = 15.55

13.25 - 2.3 = 10.95

Two of your sides equal 15.55, and the other two equal 10.95.

Hope this helps!

3 0

4 years ago

Factor the polynomial, x2 + 5x + 6

patriot [66]

Answer:

Choice b.

$x^{2} + 5\, x + 6 = (x + 3)\, (x + 2)$ .

Step-by-step explanation:

The highest power of the variable $x$ in this polynomial is $2$ . In other words, this polynomial is quadratic.

It is thus possible to apply the quadratic formula to find the "roots" of this polynomial. (A root of a polynomial is a value of the variable that would set the polynomial to $0$ .)

After finding these roots, it would be possible to factorize this polynomial using the Factor Theorem.

Apply the quadratic formula to find the two roots that would set this quadratic polynomial to $0$ . The discriminant of this polynomial is $(5^{2} - 4 \times 1 \times 6) = 1$ .

$\begin{aligned}x_{1} &= \frac{-5 + \sqrt{1}}{2\times 1} \\ &= \frac{-5 + 1}{2} \\ &= -2\end{aligned}$ .

Similarly:

$\begin{aligned}x_{2} &= \frac{-5 - \sqrt{1}}{2\times 1} \\ &= \frac{-5 - 1}{2} \\ &= -3\end{aligned}$ .

By the Factor Theorem, if $x = x_{0}$ is a root of a polynomial, then $(x - x_0)$ would be a factor of that polynomial. Note the minus sign between $x$ and $x_{0}$ .

The root $x = -2$ corresponds to the factor $(x - (-2))$ , which simplifies to $(x + 2)$ .
The root $x = -3$ corresponds to the factor $(x - (-3))$ , which simplifies to $(x + 3)$ .

Verify that $(x + 2)\, (x + 3)$ indeed expands to the original polynomial:

$\begin{aligned}& (x + 2)\, (x + 3) \\ =\; & x^{2} + 2\, x + 3\, x + 6 \\ =\; & x^{2} + 5\, x + 6\end{aligned}$ .

4 0

3 years ago

What are the zeros of the polynomial function f(x)=x3-7x2+8x+16

labwork [276]

Answer: x=4, -1

Step-by-step explanation:

Assuming you meant $x^3-7x^2+8x+16$ , the zeros of the question are x = 4 and -1.

Step 1. Replace f(x) with y.

$y = x^3-7x^2+8x+16$

Step 2. To find the roots of the equation, replace <em>y</em> with 0 and solve.

$0 = x^3-7x^2+8x+16$

Step 3. Factor the left side of the equation.

$(x-4)^2 (x+1)=0$

Step 4. Set x-4 equal to 0 and solve for <em>x</em>.

$x-4=0$

Step 5. Set $x+1$ equal to 0 and solve for <em>x</em>.

$x=-1$

The solution is the result of $x-4=0$ and $x+1=0$ .

$x=4,-1$

5 0

3 years ago