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IgorC [24]
3 years ago
15

8. The sum of two numbers is 8 less than twice the first number. Their difference is 4 less than twice

Mathematics
1 answer:
Delicious77 [7]3 years ago
7 0

Answer:

14 and 6

Step-by-step explanation:

Let's start by naming the first number x.

We can name the second number y.

We can set up equations to model our situation.

x+y=2x-8

x-y=2y-4

Let's simplify the equations.

x+y=2x-8

Subtract 2x from both sides

-x+y=-8

__________

x-y=2y-4

Subtract 2y from both sides.

x-3y=-4

Add the two equations together to eliminate x.

x-3y=-4

-x+y=-8

________

0x-2y=-12

-2y=-12

Divide both sides by -2.

y=6

The second number is 6.

Plug that back in.

x+6=2x-8

Subtract x from both sides

6=x-8

Add 8 to both sides

x=14

The first number is 14

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Answer:

The Length of third side is 52 units.

Step-by-step explanation:

Given:

Length of First side = 48

Length of second side = 20

Also given the angle between them is 90°.

Hence we can say figure shown is a right angled triangle.

For finding the third side we can use Pythagoras theorem which states that;

"If a triangle is right angled then, the Square of the hypotenuse is equal to sum of the square of the other two sides."

Third \ side ^2=First \ side^2+Second \ side^2

Hence substituting the values we get;

Third\ side^2= 48^2+20^2 = 2304+400 =2704

Now taking Square root on both side we get;

\sqrt{Third \ side^2} = \sqrt{2704}\\ Third \ side = 52 \ units

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3 years ago
The seventh grade class is raising money to have a class trip at the end of the year. They began the year with $1500. They now h
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Answer:

The percent of the increase for the money the class raised is 10 %

Step-by-step explanation:

Because if you divide 1500 by 10 you get 150 that means 150 is 10 % of 1500 and if you add 150 to 1500 you get 1650 so the increase of money the class raised is 10 %

I hope this helped :)

5 0
3 years ago
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Aleonysh [2.5K]
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denis-greek [22]

Answer:

B. 18 cm.

Step-by-step explanation:

Because they are similar, we can say that segment AC corresponds to segment DF, and segment AB corresponds to segment ED. So, we can set up a proportion.

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