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Anni [7]
3 years ago
10

Help please 6+6x4+8.................

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
6 0
,12x12=144.................
Anna11 [10]3 years ago
5 0
6+6*4+8
6+24+8
30+8
38


6+6*4+8=38
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3+-√(-3)^2 - 4(5)(-1)
Alona [7]

Answer:

Step-by-step explanation:

Easy way to do this is step by step.  Your quadratic, from your entry, must be

5x^2-3x-1.

Step by step looks like this, one thing at a time:

x=\frac{3+\sqrt{(-3)^2-4(5)(-1)} }{2(5)} becomes

x=\frac{3+\sqrt{9-(-20)} }{10} becomes

x=\frac{3+\sqrt{9+20} }{10}

and this of course is

x=\frac{3+\sqrt{29} }{10}

Do the same with the subtraction sign to get the other solution.

If you're unsure of how to enter it into your calculator, do it step by step so you don't mess up the sign.  If you enter it incorrectly, you could end up with an imaginary number when it should be real, or a real one that should be imaginary.

Just my advice as a high school math teacher.

3 0
3 years ago
Does it have an inverse if so what is it?
lidiya [134]

Answer:

no it does not have an inverse. because the determinate is 0 and you can't find the inverse of 0

6 0
2 years ago
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What is the solution to 4<br> ***25-79<br> ΧΣ- 12<br> ΧΣ 12<br> Ο χK12<br> Ο χ4 - 12
jekas [21]

Answer:

\displaystyle x \leq 12

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle -\frac{3}{4}x + 2 \leq -7<u />

<u />

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. [Subtraction Property of Equality] Isolate <em>x</em> term:                                           \displaystyle -\frac{3}{4}x \leq -9
  2. [Division Property of Equality] Isolate <em>x</em>:                                                         \displaystyle x \leq 12

Here we see that any value <em>x</em> smaller than or equal to 12 would work as a solution to the inequality.

7 0
3 years ago
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