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Taya2010 [7]
3 years ago
12

Plsss help with 4,5,6, or 7

Mathematics
1 answer:
kherson [118]3 years ago
6 0

Answer:

you did not say which question to answer

Step-by-step explanation:

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The value of -4*2 is______
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the value of -4*2 is -8 jdjdjdjdhdhdjdjdjdhdh

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andy earned $38 on monday and $34 on tuesday.how many lucky bamboo plants can he buy with the total money he earned?
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How much does each bamboo plant cost. This is impossible to solve without knowing the cost. I you have the cost i would be happy to help.
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4 years ago
The employee who created the chart made an error when computing the number of pounds of meat for one of the serving sizes .for w
lozanna [386]

Answer: b. 50

Step-by-step explanation:

Hence the employee made an error for 50 serving size.

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4 years ago
Rewrite f(x) = 2(x − 1)2 + 3 from vertex form to standard form. (2 points)
Ostrovityanka [42]

Answer:

F(x)= 4x-1 I think so hope it will help you

7 0
3 years ago
A colony of bacteria is grown under ideal conditions in a laboratory so that the population increases exponentially with time. A
Naddik [55]

Answer:

Initial bacterias = 6006000

Altought I believe is safe to assume that the values were 192,000 and 384,000 instead of 192,192,000 and 384,384,000, in that case the initial bacterias is 6000

Step-by-step explanation:

A exponential growth follows this formula:

Bacterias  = C*rⁿ

C the initial amount

r the growth rate

n the number of time intervals

Bacterias (55 hours) = 192,192,000

Bacterias (66 hours) = 384,384,000

Bacterias(55hours)=C*r^{{\frac{55-t}{t}}} \\Bacterias (66hours) = C*r^{\frac{66-t}{t}}}

If you divide both you can get the growth rate:

\frac{Bacterias (66hours)}{Bacterias(55hours)}=\frac{C*r^{\frac{66-t}{t}}}{C*r^{{\frac{55-t}{t}}}} \\\frac{384,384,000}{192,192,000} =r^{\frac{66-t}{t} -\frac{55-t}{t} } \\2 =r^{\frac{11}{t}}

So with that r = 2 and each time interval correspond to 11 years

Then replacing in one you can get the initial amount of C

Bacterias (55hours)=C*2^{\frac{55-11}{11} } 192,192,000 = C*32\\C= 6006000

7 0
3 years ago
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