Question

You are dealt two cards without replacement what is the probability the first card is one of 4 twos and second is 4 tens in a deck

Answer 1

A = drawing a two card
B = drawing a ten card

P(A) = 4/52 = 1/13
P(B|A) = P(A and B)/P(A)
P(A)*P(B|A) = P(A and B)
P(A and B) = P(A)*P(B|A)
P(A and B) = (1/13)*(4/51)
P(A and B) = 4/663
P(A and B) = 0.006033

The answer as a fraction is exactly 4/663
The answer in decimal form is approximately 0.006033