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marissa [1.9K]
4 years ago
7

Can somebody find the IQR (interquartile range) of this set of number for me please? Thank you!

Mathematics
1 answer:
GalinKa [24]4 years ago
8 0
We have 6.2, 6.8, 6.3, 8.8, 5.4, 8.9, 7.7, 8.1, 8.6, 5.5.
Let's put it in order.
5.4, 5.5, 6.2, 6.3, 6.8, ║7.7, 8.1, 8.6, 8.8, 8.9.
Subtract.
8.6-6.2
2.4
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Determine the Domain of: 8(x)=(4)/(x-9)
Charra [1.4K]

Hi !

f(x) =  \frac{4}{x - 9}

x-9 must be different from 0.

x -9 \ne0 \\ x \ne9

=  =  >  \: D_f=\mathbb{R}-\{9\}

Have a nice day ;)

4 0
2 years ago
Can someone please help me with this?
lidiya [134]
The angle formed by two tangles results in half of the difference of the two arcs. 

That is to say 

70 = .5(Major arc - minor arc)

Think of the major arc as the larger and the minor the smaller.

So therefore the difference in the two arcs = 140 (multiplying both sides of the above equation by 2.

140 = major arc - minor arc.

Another necessary idea is that the arc of a whole circle = 360 degrees, that is to say the major arc + minor arc = 360, giving us a second equation to solve.
Assuming x is the minor arc.

140 = major arc - x 
360 = major arc + x

Use linear combination and add these equations to get

500 = 2*major arc

major arc = 250
minor arc or x = 110.

The answer is 110 degrees.

8 0
3 years ago
If you draw a card with a value of four or less from a standard deck of cards I will pay you $43 if not you pay me $10. Step 1.
Vera_Pavlovna [14]

The expected value of the game is its average earnings

  • The expected value of a round is $2.23
  • The expected value when the game is played 755 times is $1683.65

<h3>How to determine the expected value of a round</h3>

There are 12 cards with a value of 4 or less.

So, the probability of selecting a card with a value of 4 or less is:

P(x \le 4) = \frac{12}{52}

The probability of selecting a card with a value more than 4 is the complement of the above probability.

So, we have:

P(x > 4) = 1 - \frac{12}{52}

P(x > 4) =  \frac{40}{52}

The expected value is then calculated as:

E(x) = \frac{12}{52} * 43 - \frac{40}{52} * 10

Evaluate

E(x) = \frac{12* 43 - 40 * 10}{52}

E(x) = \frac{116}{52}

Simplify

E(x) = 2.23

Hence, the expected value of a round is $2.23

<h3>The expected value when the game is played 755 times</h3>

In (a), we have:

E(x) = 2.23

In probability, we have:

E(nx) = n * E(x)

So, we have:

E(755x) = 755 * 2.23

E(755x) = 1683.65

Hence, the expected value when the game is played 755 times is $1683.65

Read more about expected values at:

brainly.com/question/15858152

6 0
3 years ago
The radius of a circle is 6 inches. What is the length of a 135-degree arc?
svp [43]
14.14 inches

Convert 135° into radians. 135*2pi/360=3pi/4.
6*3pi/4=18pi/4=9pi/2=14.14

Another viable method is to do 2pi*6*135/360=14.14
8 0
2 years ago
What number can be added to -2 to get a sum of 0?
levacccp [35]







Answer = 2
|-------------------|-----------------|
5 0
4 years ago
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