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Mashutka [201]
3 years ago
13

A caterpillar eats 75 leaves in 5 hours. How many leaves will the caterpillar eat in 8 hours if it continues to eat at the same

rate?
Mathematics
2 answers:
Dahasolnce [82]3 years ago
3 0

Answer:

120 leaves

Step-by-step explanation:

If the caterpillar eats 75 leaves in 5 hours and continues to eat at the same rate, the number of leaves eaten is simple, 120 leaves.

How I found the answer:

First, I divided 75 by 5 and got 15, then I multiplied 8 to 15 and got 120.

Aneli [31]3 years ago
3 0
Answer: 120 leaves

If you divide 75 and 5 you would get 15. And then you would multiply 15 to 8 to get 120.

You would divide 75 and 5 because you’ll need to find how many minutes the caterpillar ate on one leaf which would be 15 minutes. You would then multiply 15 and 8 and you’d get 120. So, 120 leaves is the answer.
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3 0
3 years ago
In a fruit cocktail, for every 72 ml of orange juice you need 56 ml of apple juice and 120 ml of coconut milk. What is the ratio
olasank [31]

Answer:

7 : 15 : 9

Step-by-step explanation:

The GCF is 8:

56/8 = 7

120/8 = 15

72/8 = 9

6 0
2 years ago
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Help ?!-10+3x=8 <br> X=??
jekas [21]
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The opposite of a negative is positive, so you can move negative ten to the other side of the problem by adding ten. Make sure that you do operations on both sides. Once you add, you have 3x=18. When a number is right next door to an x, it means it is being multiplied. To get rid of the three, divide by three on both sides. Now your get x=6, which is your answer. Hopefully, I explained this well! :D
8 0
2 years ago
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What is the Derivative of x^3-2
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4 0
3 years ago
The time needed to complete a final examination in a particular college course is normallydistributed with a mean of 80 minutes
Artist 52 [7]

Answer:

a) 0.023

b) 0.286

c) 10 students will be unable to complete the exam inthe allotted time.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 80 minutes

Standard Deviation, σ = 10 minutes

We are given that the distribution of time to complete an exam is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(completing the exam in one hour or less)

P(x < 60)

P( x < 60) = P( z < \displaystyle\frac{60 - 80}{10}) = P(z < -2)

Calculation the value from standard normal z table, we have,  

P(x < 60) =0.023= 2.3\%

b) P(complete the exam in more than 60 minutes but less than 75 minutes)

P(60 \leq x \leq 75) = P(\displaystyle\frac{60 - 80}{10} \leq z \leq \displaystyle\frac{75-80}{10}) = P(-2 \leq z \leq -0.5)\\\\= P(z \leq -0.5) - P(z < -2)\\= 0.309- 0.023 = 0.286= 28.6\%

c) P(completing the exam in more than 90 minutes)

P(x > 90)

P( x > 90) = P( z > \displaystyle\frac{90 -80}{10}) = P(z > 1)

= 1 - P(z \leq 1)

Calculation the value from standard normal z table, we have,  

P(x > 90) = 1 - 0.8413 = 0.1587 = 15.87\%

15.87% of children of class will require more than 90 minutes to complete the test.

Number of children =

\dfrac{15.87}{100}\times 60 = 9.52\approx 10

Approximately, 10 students of class will require more than 90 minutes to complete the test.

4 0
3 years ago
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