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2 years ago

Keona pours 128 ounces of water into a jar 3 times to fill it. How many pints of water does it take to fill the jar?

Mathematics

2 answers:

snow_lady [41]2 years ago

8 0

Answer:

There are 16 ounces in a pint. :D hope this helps!

Step-by-step explanation:

uranmaximum [27]2 years ago

3 0

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Oki so this is the 3rd time ive asked this and i keep forgetting to put in the qeustion im very sorry

Zarrin [17]

The answer is greater than one. :)

3 0

2 years ago

Read 2 more answers

Suppose an identical ladder was put against a building that was 18 feet high and the ladder reached the top of the building. How

nikdorinn [45]

The distance between the bottom of the ladder be from the base of the building will be 17.32 ft.

<h3>What is the Pythagorean theorem?</h3>

It states that in the right-angle triangle the hypotenuse square is equal to the sum of the square of the other two sides.

As we can see in the figure the length of the ladder is 20 ft and the base of the ladder is 10 ft from the base of the building.

By using the Pythagorean theorem we will calculate the distance between the tip of the ladder and the base of the building.

H² = 20² - 10²

H²= 400 - 300

H² = 300

H = √300

H = 17.32 ft.

Therefore the distance between the bottom of the ladder is from the base of the building will be 17.32 ft.

To know more about the Pythagorean theorem follow

brainly.com/question/343682

#SPJ1

7 0

1 year ago

Someone please help me??

lapo4ka [179]

The standard equation of a circle with centre (xc,yc) and radius R is given by

$(x-x_c)^2+(y-y_c)^2=R^2$

Substituting
centre (xc,yc) = (4,-3)
R=2.5

The equation is therefore

$(x-x_c)^2+(y-y_c)^2=R^2$
$(x-4)^2+(y-(-3))^2=2.5^2$
$(x-4)^2+(y+3)^2=2.5^2$ or
(x-4)^2+(y+3)^2=6.25

7 0

2 years ago

Expand $\left(x^2 \frac{1}{x}\right)^3$. (Write the terms with higher degree first, so for example an $x^2$ term would come befo

Ilya [14]

Answer:

$x^6+3x^3+3+\dfrac{1}{x^3}$

Step-by-step explanation:

We can use the pascal triangle to find the coefficients of the expasion of the cube. It holds that

$(x^2 + \dfrac{1}{x})^3=(x^2)^3+3(x^2)^2\dfrac{1}{x}+3x^2(\dfrac{1}{x})^2+(\dfrac{1}{x})^3\\\\=x^6+3x^4\dfrac{1}{x}+3x^2\dfrac{1}{x^2}+\dfrac{1}{x^3}\\\\=x^6+3x^3+3+\dfrac{1}{x^3}$

4 0

3 years ago

2(x+3)^(2)+8=0 Solve.

olga2289 [7]

Answer:

2i-3

Step-by-step explanation:

2(x+3)²=-8

(x+3)²=-4

x+3=2i

x=2i-3

7 0

2 years ago