Write a division problem that results in a quotient that is greater than 200 and less than 250

A toy is shaped as a triangular prism. The toy has a

Anettt [7]

Answer:

$\huge\boxed{\sf h = 6.75 \ in.}$

Step-by-step explanation:

Given Data:

Base area = $A_{B}$ = 108 in.²

Volume = V = 729 in.³

Required:

Height = h = ?

Formula:

$V=A_{B}h$

Solution:

For h, rearranging formula:

$\displaystyle h = \frac{V}{A_{B}} \\\\h =\frac{729 \ in.^3}{108 \ in.^2} \\\\h = 6.75 \ in.\\\\\rule[225]{225}{2}$

4 0

2 years ago

The tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm2 and a stand

Elanso [62]

Answer:

95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

Yes, this data suggest that the tensile strength was changed after the adjustment.

Step-by-step explanation:

We are given that the tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm 2 and a standard deviation of 2.15.

A machine was recently adjusted and a sample of 50 items were taken to determine if the mean tensile strength has changed. The mean of this sample is 74.28. Assume that the standard deviation did not change because of the adjustment to the machine.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean strength of 50 items = 74.28

$\sigma$ = population standard deviation = 2.15

n = sample of items = 50

$\mu$ = population mean tensile strength after machine was adjusted

Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level of

significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $74.28-1.96 \times {\frac{2.15}{\sqrt{50} } }$ , $74.28+1.96 \times {\frac{2.15}{\sqrt{50} } }$ ]

= [73.68 kg/mm2 , 74.88 kg/mm2]

Therefore, 95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

Yes, this data suggest that the tensile strength was changed after the adjustment as earlier the mean tensile strength was 72 kg/mm2 and now the mean strength lies between 73.68 kg/mm2 and 74.88 kg/mm2 after adjustment.

8 0

3 years ago

What is the solution of the equation √2x-3-3=6? A) 42 B) 39 C) 3 D) 6

Firlakuza [10]

Answer:

42

Step-by-step explanation:

√2x-3-3=6

√2x-3=6+3

√2x-3=9

2x-3=9^2

2x=81+3

X=84/2

X=42

So value of X is 42

4 0

3 years ago

It takes three identical water pumps 8 hours to fill a pool, What is the constant of variation?

BaLLatris [955]

Answer:

Constant of variation is 24.

Step-by-step explanation:

Inverse variation states that a relationship between two variables in which the product is remain constant.

If one variable increases then, the other one decreases in proportion so that the product is unchanged,

if y is inversely proportional to x i.e $y \propto\frac{1}{x}$ or

$y =\frac{k}{x}$ ;where k is the constant of variation.

It is given that 3 identical water pumps takes 8 hours to fill a pool,

since, it will take less time with more pumps, so it is an inverse variation.

By definition of inverse variation;

$time = \frac{k}{pump}$

Substitute the values to solve for k;

$8 = \frac{k}{3}$

Multiply by 3 to both sides we get;

$8 \times 3 = \frac{k}{3} \times 3$

Simplify:

k = 24

Therefore, the constant of variation is, 24

3 0

3 years ago

PLZ HELP MEEEEE!!!! ILL GIVE YOU BRAINLY!!

valkas [14]

Answer:

Step-by-step explanation: -13, 9

8 0

3 years ago