Solve ALL please . work needed 5x-1=x+115 3+5q=9+4q 2b+4=-18-9b
1 answer:
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Answer:
D
Step-by-step explanation:
Combine like terms
Let side be "a" cm. So another side is (30-2a)/2=15-a
S=ab=a(15-a)=15a-a^2 - parabola
maximum when a = -15/-2=7.5 cm
When a=7.5 all sides are 7.5 cm
So it's a square. S=a*a=7.5*7.5=56.25 cm^2 - max
There is no global minimun for S.(look at the graphic)
S=ab=a(15-a)=15a-a^2 - parabola
maximum when a = -15/-2=7.5 cm
When a=7.5 all sides are 7.5 cm
So it's a square. S=a*a=7.5*7.5=56.25 cm^2 - max
There is no global minimun for S.(look at the graphic)
To find out the answer, treat both machines as lines. The answer can be found when you have equations for each machine. The first step of that would be to make an equation for "line" J, so find the slope using two sets of its given coordinates, I'll use (3,90) and (6,180).
Substitute in the x and y values
Subtract
Divide
30
Now that you know 30 is the slope, you can plug that and one set of coordinates, I'll use (3,90) into point-slope form.
y - y_1 = m(x - x_1) Substitute in your x and y coordinates and slope
y - 90 = 30(x - 3) Use the Distributive Property
y - 90 = 30x - 90 Add 90 to both sides
y = 30x
Now you have the equations for both machines. You want to find out how many candies each machine packages in 11 minutes, and x represent minutes, so plug 11 into the x value for both equations.
Machine J
y = 30x Substitute
y = 30 (11) Multiply
y = 330
Machine J packs 330 candies in 11 minutes.
Machine K
y = 26x Substitute
y = 26 (11) Multiply
y = 286
Machine K packs 286 candies in 11 minutes.
Finally, to find out how many more candies Machine J packs than Machine K, subtract the two values.
330 - 286 = 44
Machine J can pack 44 more candies than Machine K in 11 minutes.
30
Now that you know 30 is the slope, you can plug that and one set of coordinates, I'll use (3,90) into point-slope form.
y - y_1 = m(x - x_1) Substitute in your x and y coordinates and slope
y - 90 = 30(x - 3) Use the Distributive Property
y - 90 = 30x - 90 Add 90 to both sides
y = 30x
Now you have the equations for both machines. You want to find out how many candies each machine packages in 11 minutes, and x represent minutes, so plug 11 into the x value for both equations.
Machine J
y = 30x Substitute
y = 30 (11) Multiply
y = 330
Machine J packs 330 candies in 11 minutes.
Machine K
y = 26x Substitute
y = 26 (11) Multiply
y = 286
Machine K packs 286 candies in 11 minutes.
Finally, to find out how many more candies Machine J packs than Machine K, subtract the two values.
330 - 286 = 44
Machine J can pack 44 more candies than Machine K in 11 minutes.