What is the measure of tsq?
1 answer:
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Answer: There is an asymptote at x = 4 and 2
and hole at x=2
Explanation:
To find vertical asymptote simply equate denominator to zero and find the value of x which is the vertical asymptote.
and hole is the point where numerator and denominator gives equal value
So, to find hole find fractions of numerator and denominator separately the common factor is the hole.
Here after factorisation the given function
Here, (x-2) is the common factor in numerator and denominator is the hole and value of x at denominator after equating to zero is x=2 ,4