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ololo11 [35]
3 years ago
12

There are 59 participants in a pie eating contest. Nadia placed third, and Johnny placed in the exact middle of all the particip

ants. How many pie-eating participants placed between Nadia and Johnny?
Mathematics
1 answer:
zepelin [54]3 years ago
8 0

Answer:

27 students

Step-by-step explanation:

59/2

29.5

29.5 rounded up to 30

30-3

27 students

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Circle O has a circumference of approximately 2507 ft.
Gnom [1K]

Answer:

8

Step-by-step explanation:

4 0
4 years ago
Simplify. (-2/3) - (3/5)
yKpoI14uk [10]
Okay so here you go 

<span>Decimal Form: -1.266667
</span>
Fraction form: -19/15

hears how: 
Simplify brackets
-2/3 - 3/5

Simplify: -19/15


5 0
3 years ago
Read 2 more answers
The power supplied to a typical black-andwhite television set is 48.1 W when the set is connected to 72 V. How much electric ene
Mnenie [13.5K]

Answer:

Energy consumed = 1.73× 10⁵ J

Step-by-step explanation:

Given:

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8 0
4 years ago
The table shows the number of blue marbles and red marbles that four friends have collected.
anygoal [31]

Answer:

Gretchen

Step-by-step explanation

Jasmine: 12/10 : 1

Aaron: 3/2 : 1

Lucian: 1 : 1

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3 years ago
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Find the distance from point (-1, 3) to the line 5 x - 4 y = 10.
Wewaii [24]

We could use the formula, derive the formula, or just work it out for this case.  Let's do the latter.

The distance of a point to a line is the length of the perpendicular from the line to the point.

So we need the perpendicular to 5x-4y=10 through (-1,3).  To get the perpendicular family we swap x and y coefficients, negating one.  We get the constant straightforwardly from the point we're going through:

4x + 5y = 4(-1)+5(3) = 11

Those lines meet at the foot of the perpendicular, which is what we're after.

4x + 5y = 11

5 x - 4y = 10

We eliminate y by multiplying the first by four, the second by five and adding.

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x = 94/41

y  = (11 - 4x)/5 = 15/41

We want the distance from (-1,3) to (94/41,15/41)

d = \sqrt{ (-1 - 94/41)^2 + (3 - 15/41)^2 } = \dfrac{27}{\sqrt{41}}

8 0
4 years ago
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