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ziro4ka [17]
3 years ago
8

How do I simplify 4b-7-15b+3

Mathematics
1 answer:
natta225 [31]3 years ago
8 0
First you combine like terms which are 4b and -15b which turn into -11b and then you combine like terms again which are -7 and +3 which gets you to -4. So your final answer is -11b-4
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Which equation represents the line that is perpendicular to and passes through (-40,20)?
emmasim [6.3K]

The equation of the perpendicular line to the given line is: y = -5/4x - 30.

<h3>What is the Equation of Perpendicular Lines?</h3>

The slope values of two perpendicular lines are negative reciprocal of each other.

Given that the line is perpendicular to y = 4/5x+23, the slope of y = 4/5x+23 is 4/5. Negative reciprocal of 4/5 is -5/4.

Therefore, the line that is perpendicular to it would have a slope (m) of -5/4.

Plug in m = -5/4 and (x, y) = (-40, 20) into y = mx + b to find b:

20 = -5/4(-40) + b

20 = 50 + b

20 - 50 = b

b = -30

Substitute m = -5/4 and b = -30 into y = mx + b:

y = -5/4x - 30

The equation of the perpendicular line is: y = -5/4x - 30.

Learn more about about equation of perpendicular lines on:

brainly.com/question/7098341

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8 0
1 year ago
NEED ANSWER ASAP!!! WILL GIVE BRAINLIEST TO WHO ANSWERS FIRST!
alexandr1967 [171]

Answer:

x < - 4

Step-by-step explanation:

Given

2x - 2 > 4x + 6 ( subtract 2x from both sides )

- 2 > 2x + 6 ( subtract 6 from both sides )

- 8 > 2x ( divide both sides by 2 )

- 4 > x , thus

x < - 4

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2 years ago
In which number does the digit 5 have ten times the value of the digit 5 in 1,452
Salsk061 [2.6K]

Answer:

Tens place

Step-by-step explanation:

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3 years ago
Here is a centimetre square grid.<br> Draw a shape with an area of 11cm squared.
aksik [14]

Hi

Answer in photo

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3 years ago
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Trigonometric equations<br><br> 5sinx = 3sinx + square root of 2
Lera25 [3.4K]

\qquad\qquad\huge\underline{{\sf Answer}}♪

Let's solve for x ~

\qquad \sf  \dashrightarrow \:5 \sin(x)  = 3 \sin(x)   +  \sqrt{2}

\qquad \sf  \dashrightarrow \:5 \sin(x)  - 3 \sin(x)  =  \sqrt{2}

\qquad \sf  \dashrightarrow \:2 \sin(x)  =  \sqrt{2}

\qquad \sf  \dashrightarrow \: \sin(x)  =  \sqrt{2}  \div 2

\qquad \sf  \dashrightarrow \: \sin(x) =  \frac{1}{ \sqrt{2} }

\qquad \sf  \dashrightarrow \:x = 45 \degree \:  \: or \:  \:  \frac{\pi}{4}  \: rad

・ .━━━━━━━†━━━━━━━━━.・

4 0
2 years ago
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