By doing the math. if you do the math then you will get the answer.
so yea. do the math lol
Nickels n
quarters q
I: 3.15=n*0.05+q*0.25
II: n+q=23
isolate n in II:
n+q=23
n=23-q
substitute n in I:
3.15=n*0.05+q*0.25=
3.15=(23-q)*0.05+q*0.25
3.15=(23-q)*(1/20)+(q/4)
3.15=(23/20)-q/20+(q/4)
3.15=1.15-(4*q/20)
2=q/5
10=q
insert q=10 into II:
n+q=23
n+10=23
n=13
so c) 3 more nickels than quarters
Answer:
can u give more information about the problem, like what are the options?
Step-by-step explanation:
Answer is x=-12
To solve:
-3x=36
Step 1: Change -3x to 3x and 36 to -36.
3x=-36
Step 2: Divide both sides by 3.
3x/3=-36/3
So, the answer is x=-12.