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Nesterboy [21]
3 years ago
12

A skier is trying to decide whether or not to buy a season ski pass. A daily pass costs $65. A season pass costs $400. The skier

would have to rent skis with either pass for $30 per day. How many days would the skier have to go skiing in order to make the season pass less expensive than the daily pass?
Mathematics
1 answer:
Vlad [161]3 years ago
3 0
Let x be the number of days.

Daily pass:
65x + 30x
95x

Season pass:
400 + 30x

95x > 400 + 30x
65x > 400
x > 6.15

The number of days can't be 6.15, so you must round. You can't go down because then the price will be more expensive, so you have to round up.

It would take 7 days until the season pass is less expensive than the daily pass.
----------------------
You can check this by plugging in the x.

95x > 400 + 30x
95(7) > 400 + 30(7)
665 > 400 + 210
665 > 600
The daily pass is more expensive than the season pass.
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Answer:

See answer below

Step-by-step explanation:

You are missing data such as the angle of the boat next to Dolores. I found an exercise similar to this, and I'm going to show it here and use the missing data to show you how to do it:

<u>Dolores is on a bridge that is 45 feet above a lake. She sees a boat at a 30 degree angle of depression. What is Dolores' approximate horizontal distance from the boat?</u>

<u></u>

According to that, I will use the angle of 30° to do this, but the distance of 42 feet.

Now, we can see this as a triangle. Dolores is on a bridge 42 feet above a lake, this 42 feet distance should be one side of the triangle (The vertical forming the 90° angle), and the boat that is on the lake, is seen with an angle of 30°. So the distance of the boat, to the spot where dolores is, under the bridge would be the horizontal side.

With this, we have the opposite side (a) and the adyacent side (b) of the triangle, and we have the angle, therefore:

tanα = a/b

Replacing we have:

tan30° = 42/b

b = 42 / tan30°

b = 72.75 feet

Hope this helps

4 0
3 years ago
Given congruent triangles name the corresponding sides and corresponding angles
Alborosie

Answer:

See explanation

Step-by-step explanation:

Given \triangle ABC\cong \triangle ADC

According to the order of the vertices,

  • side AB in triangle ABC (the first and the second vertices) is congruent to side AD in triangle ADC (the first and the second vertices);
  • side BC in triangle ABC (the second and the third vertices) is congruent to side DC in triangle ADC (the second and the third vertices);
  • side AC in triangle ABC (the first and the third vertices) is congruent to side AC in triangle ADC (the first and the third vertices);
  • angle BAC in triangle ABC is congruent to angle DAC in triangle ADC (the first vertex in each triangle is in the middle when naming the angles);
  • angle ABC in triangle ABC is congruent to angle ADC in triangle ADC (the second vertex in each triangle is in the middle when naming the angles);
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6 0
4 years ago
Please answer this correctly
prohojiy [21]

Answer:

Hi there!

The answer to the answer to this question is: 1,399.286

Step-by-step explanation:

There is two methods you can solve this question, either with long division or short division in this case I chose short division and got 1,399.286

6 0
3 years ago
Which of the following lines has a slope of -1/3 and a y-intercept of 6? x - 3y = 6 x + 3y = 18 3y - x = 18
erastovalidia [21]
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Read 2 more answers
PLASE ANSWER THIS QUESTION ​I GIVE YOU 18 POINTS
sukhopar [10]

Answer:

(a) 144

(b) 117

(c) 360

(d) 588

(e) 5472

Step-by-step explanation:

To find the LCM of two numbers, first find the prime factorization of each number. Then the LCM is the product of common and not common factors with the larger exponent.

2.

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72 = 2^3 \times 3^2

144 = 2^4 \times 3^2

LCM = 2^4 \times 3^2 = 8 \times 9 = 144

(b)

39 = 3 \times 13

117 = 3^2 \times 13

LCM = 3^2 \times 13 = 117

(c)

72 = 2^3 \times 3^2

90 = 2 \times 3^2 \times 5

LCM = 2^3 \times 3^2 \times 5 = 360

(d)

84 = 2^2 \times 3 \times 7

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LCM = 2^2 \times 3 \times 7^2 = 588

(e)

152 = 2^3 \times 19

288 = 2^5 \times 3^2

LCM = 2^5 \times 3^2 \times 19 = 5472

6 0
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