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Naily [24]
3 years ago
10

What is -1.1 repeating as a fraction

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
4 0

Hey \\ There!

\frac{-1.1}{1} ( \frac{10}{10} )\\ \\ -1.1(10) = -11   \\ \\ 1(10)= 10 \\ \\ \\  Fraction:  \frac{-11}{10} this is also equal to: -1\frac{1}{10}

Your answer would probably be: \frac{-11}{10} =  -1\frac{1}{10}

Good luck on your assignment and enjoy your day! 

~MeIsKaitlyn:)
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Para ampliar uma sala quadrada, foram acrescentados 4 metros em seu comprimento e 2 metros em sua largura, conforme a figura. Qu
ollegr [7]

Answer:

b) x^2 + 6x + 8

Step-by-step explanation:

Para ampliar la habitación cuadrada, se agregaron 4 metros de largo y 2 metros de ancho, como se muestra en la figura.

Deje que la longitud y el ancho de la habitación antes de la expansión sean x.

La nueva longitud de la sala es (x + 4).

El nuevo ancho de la sala es (x + 2).

La nueva área de la sala será:

(x + 4)(x + 2)\\x^2 + 2x + 4x + 8\\x^2 + 6x + 8\\\\

Esa es la nueva área de la habitación.

3 0
3 years ago
The shorter leg of a right triangle is 7cm shorter than the longer leg. The hypotenuse is 7cm longer then the linger leg. What i
Gelneren [198K]

The shorter leg is 21cm, longer leg is 28 cm and hypotenuse is 35cm.

Step-by-step explanation:

Let,

The longer leg = x

The shorter leg = x-7

Hypotenuse = x+7

Using Pythagoras theorem;

a^2+b^2=c^2\\(x-7)^2+(x)^2=(x+7)^2\\x^2-14x+49+x^2=x^2+14x+49\\2x^2-14x+49-x^2-14x-49=0\\x^2-28x=0\\x(x-28)=0\\

Either,

x= 0

Or,

x-28=0      =>x=28

As length cannot be zero, therefore,

Longer side = 28cm

Shorter side = x-7 = 28-7 = 21cm

Hypotenuse = x+7 = 28+7 = 35cm

The shorter leg is 21cm, longer leg is 28 cm and hypotenuse is 35cm.

Keywords: triangle, pythagoras theorem

Learn more about triangles at:

  • brainly.com/question/9323337
  • brainly.com/question/9381080

#LearnwithBrainly

5 0
3 years ago
Find an expression for the area enclosed by quadrilateral ABCD below.
Helga [31]
  • ∆ABD is right angled hence area:-

\\ \sf\longmapsto \dfrac{1}{2}bh

\\ \sf\longmapsto \dfrac{1}{2}(4x)(3x)

\\ \sf\longmapsto \dfrac{1}{2}(12x^2)

\\ \sf\longmapsto 6x^2

There is only one option containing 6x^2 i.e Option D.

Hence without calculating further

Option D is correct

6 0
3 years ago
Read 2 more answers
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Over [174]

Answer:

That equation doesn't make sense, so this equation means "no solution"

Step-by-step explanation:

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3 years ago
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12 not sure if it's true or not.
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