Equation 1: y = -2x + 1
Equation 2: y = 2x - 3
Since both equations already have y isolated, we are able to simply set the right side of both equations equal to each other. Since we know that the value of y must be the same, we can do this.
-2x + 1 = 2x - 3
1 = 4x - 3
4 = 4x
x = 1
Then, we need to plug our value of x back into either of the original two equations and solve for y. I will be plugging x back into equation 2 above.
y = 2x - 3
y = 2(1) - 3
y = 2 - 3
y = -1
Hope this helps!! :)
10 = 2x5
4 = 2x2
LCM + 2x2x5 = 20 <=== smallest number of bracelets and hair bow to buy
Answer:
Approximatley 5.8 units.
Step-by-step explanation:
We are given two angles, ∠S and ∠T, and the side opposite to ∠T. We need to find the unknown side opposite to ∠S. Therefore, we can use the Law of Sines. The Law of Sines states that:

Replacing them with the respective variables, we have:

Plug in what we know. 20° for ∠S, 17° for ∠T, and 5 for <em>t</em>. Ignore the third term:

Solve for <em>s</em>, the unknown side. Cross multiply:

Answer:
The answer to your question is the last option
Step-by-step explanation:
Quadratic equation
2 = - x + x² - 4
Order the equation from the highest power to the lowest power. Do not consider 2 because it is not consider in the options given.
x² - x - 4 = 0
Identify a, b and c
(1) x² -(1) x - 4 = 0
a = 1 b = -1 c = - 6
Substitution

For question one:
First class goes from 8:00 to 9:00 second class starts 10 mins later at 9:10 and goes to 10:10. Ten minute break again 3rd class starts at 10:20, goes to 11:20. 10 min break again, fourth class starts 10 mins later at 11:30 and goes to 12:30. The answer for 1 is 12:30