The rest of the question is the attached figure.
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Δ AYW a right triangle at Y ⇒⇒⇒ ∴ WA² = AY² + YW²
And AY = YB ⇒⇒⇒ ∴ WA² = YB² + YW² → (1)
Δ BYW a right triangle at Y ⇒⇒⇒ ∴ WB² = BY² + YW² → (2)
From (1) , (2) ⇒⇒⇒ ∴ WA = WB →→ (3)
Δ CXW a right triangle at Y ⇒⇒⇒ ∴ WC² = CX² + XW²
And CX = XB ⇒⇒⇒ ∴ WC² = XB² + XW² → (4)
Δ BXW a right triangle at Y ⇒⇒⇒ ∴ WB² = XB² + XW² → (5)
From (4) , (5) ⇒⇒⇒ ∴ WC = WB →→ (6)
From (3) , (6)
WA = WB = WC
given ⇒⇒⇒ WA = 5x – 8 and WC = 3x + 2
∴ <span> 5x – 8 = 3x + 2</span>
Solve for x ⇒⇒⇒ ∴ x = 5
∴ WB = WA = WC = 3*5 + 2 = 17
The correct answer is option D. WB = 17
Answer:
5cm
Step-by-step explanation:
Given area of trapezium = 31.5 sq. cm
Length of parallel sides = 7.3cm and 5.3cm
Formula to calculate area of trapezium is
1/2*(sum of parallel sides)*perpendicular distance between parallel sides
sum of parallel sides = (7.3 + 5.3) = 12.6cm
substituting value of area given and sum of parallel sides we have
31.5 = 1/2* 12.6 * perpendicular distance between parallel sides
(31.5 * 2)/12.6 = perpendicular distance between parallel sides
perpendicular distance between parallel sides = 63/12.6 = 5
Therefore perpendicular distance between parallel sides for given trapezium is 5cm.
Huh I 8 so yeah bye nice talking to ya
Answer: X=1
Step-by-step explanation: 5x+8-3x=10
Combine like terms; 5x + (-3x) = 2x
Rewrite; 2x+8=10
Get “x” alone; 2x+8=10
-8. -8
Simply divsion; 2x=2
X=1
Answer:
Iced Tea
Step-by-step explanation:
water is not normally 7.99$ so i'm guessing Iced tea depending on the fact that it could be a large or extra large which could get to the total of 7.99$