<em><u>D.</u></em><em><u> </u></em>
<em><u>Explanation</u></em><em><u>:</u></em>
<em><u>a landscape of farmland bisected by long straight roads"</u></em>
<em><u>divide into two parts.</u></em>
<em><u>hope</u></em><em><u> I</u></em><em><u> help</u></em><em><u> you</u></em><em><u> ☺️</u></em><em><u>❤️</u></em>
<em><u>:</u></em><em><u>)</u></em><em><u> </u></em><em><u> </u></em><em><u>:</u></em><em><u>></u></em>
Answer:
Step-by-step explanation:
A1. C = 104°, b = 16, c = 25
Law of Sines: B = arcsin[b·sinC/c} ≅ 38.4°
A = 180-C-B = 37.6°
Law of Sines: a = c·sinA/sinC ≅ 15.7
A2. B = 56°, b = 17, c = 14
Law of Sines: C = arcsin[c·sinB/b] ≅43.1°
A = 180-B-C = 80.9°
Law of Sines: a = b·sinA/sinB ≅ 20.2
B1. B = 116°, a = 11, c = 15
Law of Cosines: b = √(a² + c² - 2ac·cosB) = 22.2
A = arccos{(b²+c²-a²)/(2bc) ≅26.5°
C = 180-A-B = 37.5°
B2. a=18, b=29, c=30
Law of Cosines: A = arccos{(b²+c²-a²)/(2bc) ≅ 35.5°
Law of Cosines: B = arccos[(a²+c²-b²)/(2ac) = 69.2°
C = 180-A-B = 75.3°
Answer:
x = 60°
Step-by-step explanation:
AOB Center: O AB: diameter
arc ADB = 180°
arc DB = 180 - arc AD = 80°
x = 1/2 x ( arc DB + arc AC) = 1/2 x (80 + 40) = 60°
