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Jet001 [13]
3 years ago
10

Which of the following is the contrapositive of the statement "If I travel, I will go to France"?

Mathematics
2 answers:
shtirl [24]3 years ago
7 0
Contrapositive is basically the converse of the statement. For example, the contrapositive of the statement "If the color is blue, then the fence is blue" is "If the color is not blue, the fence is not blue". Our answer choice that is correct is choice A.

:)

Tom [10]3 years ago
6 0

Answer:

A. If I will not go France, then I will not travel.

Step-by-step explanation:

We are given the statement, 'If I travel, I will go to France'.

Here, we have,

Hypothesis : If I travel.

Conclusion : I will go to France.

Contra-positive statement is obtained by switching the hypothesis and conclusion of a conditional statement and negate them both.

So, the contra-positive statement of the given statement is,

A. If I will not go France, then I will not travel.

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What is the answer for 12a-a
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11a.
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Is it possible to have a regular polygon with measure of each exterior angle as 22
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Answer:

No

Step-by-step explanation:

Number of sides of a polygon = 360°/measure each exterior angle

= 360°/22

= 16.36°

Since, answer is not a whole number, thus, a regular polygon with measure of each exterior angle as 22⁰ is not possible.

Thus the answer is no.

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The zoom feature on a copier sets the percent size of a copy. Carol wants to make a 150% copy of a photograph. The original phot
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In triangle ABC, ∠ABC=70° and ∠ACB=50°. Points M and N lie on sides AB and AC respectively such that ∠MCB=40° and ∠NBC=50°. Find
Sever21 [200]

Answer:

∠NMC  = 50°

Step-by-step explanation:

The interpretation of the information given in the question can be seen in the attached images below.

In ΔABC;

∠ A + ∠ B + ∠ C = 180°    (sum of angles in a triangle)

∠ A + 70°  + 50°  = 180°

∠ A = 180° - 70° - 50°

∠ A =  180° - 120°

∠ A =  60°

In ΔAMN ; the base angle are equal , let the base angles be x and y

So; x = y   (base angle of an equilateral  triangle)

Then;

x + x + 60° = 180°

2x +  60° = 180°

2x = 180° - 60°

2x = 120°

x = 120°/2

x = 60°

∴ x = 60° , y = 60°

In ΔBQC

∠a + ∠e + ∠b = 180°

50° + ∠e + 40° = 180°

∠e = 180° - 50° - 40°

∠e = 180° - 90°

∠e = 90°

At point Q , ∠e = ∠f = ∠g = ∠h = 90°  (angles at a point)

∠i  = 50° - 40° = 10°

In ΔNQC

∠f + ∠i   + ∠j = 180°

90° + 10° + ∠j = 180°

∠j  = 180° - 90°-10°

∠j  = 180° - 100°

∠j  = 80°

From  line AC , at point N , ∠y + ∠c + ∠j = 180°   (sum of angles on a straight line)

60° + ∠c + ∠80° = 180°

∠c  = 180° - 60°-80°

∠c  = 180° - 140°

∠c  = 40°

Recall that :

At point Q , ∠e = ∠f = ∠g = ∠h = 90°  (angles at a point)

Then In Δ NMC ;

∠d + ∠h + ∠c = 180°   (sum of angles in a triangle)

∠d + 90° + 40° = 180°

∠d  = 180° - 90° -40°

∠d  = 180° - 130°

∠d  = 50°

Therefore, ∠NMC = ∠d  = 50°

3 0
3 years ago
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