Find the values of t so that the tangent line to the given curve is contains the given point? Given r(t)=2ti+t^2j-t^2k at point
(0,-4,4)
1 answer:
Answer:
t = -2,2
Step-by-step explanation:
The curve equation,
Let at t=a tangent to the curve.
Equation of tangent:
L(k) = r(a) + k r'(a)
Put t=a
Equation of tangent:
Tangent passing through (0,-4,4)
Therefore,
2a + 2k = 0 ⇒ k = -a
At t = -2,2 tangent line to the curve passing through (0,-4,4)
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