Answer:
-6
-6i
6i
6
Step-by-step explanation:
1) √4 . √-3 . √-3
![$ \sqrt{4} = 2 $](https://tex.z-dn.net/?f=%24%20%5Csqrt%7B4%7D%20%3D%202%20%24)
![$ \sqrt{-3} . \sqrt{-3} = (\sqrt{-3})^2 $](https://tex.z-dn.net/?f=%24%20%5Csqrt%7B-3%7D%20.%20%5Csqrt%7B-3%7D%20%3D%20%28%5Csqrt%7B-3%7D%29%5E2%20%24)
-6
2) √-4 . √-3 . √-3
.
Therefore,
- 6i
3) √4 . √3 . √-3
![$ \sqrt{4} = 2 $](https://tex.z-dn.net/?f=%24%20%5Csqrt%7B4%7D%20%3D%202%20%24)
![$ \sqrt{3} . \sqrt{-3} = (\sqrt{3})^2 . \sqrt{-1} $](https://tex.z-dn.net/?f=%24%20%5Csqrt%7B3%7D%20.%20%5Csqrt%7B-3%7D%20%3D%20%28%5Csqrt%7B3%7D%29%5E2%20.%20%5Csqrt%7B-1%7D%20%24)
6i
4) √4 . √3 . √3
![$ \sqrt{4} = 2 $](https://tex.z-dn.net/?f=%24%20%5Csqrt%7B4%7D%20%3D%202%20%24)
![$ \sqrt{3} . \sqrt{3} = (\sqrt{3})^2 = 3 $](https://tex.z-dn.net/?f=%24%20%5Csqrt%7B3%7D%20.%20%5Csqrt%7B3%7D%20%3D%20%28%5Csqrt%7B3%7D%29%5E2%20%20%3D%203%20%24)
Therefore, √4 . √3 . √3 = 2 . 3 = 6
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#2 +65?
Answer:
a=-1
If you need explanation please comment
Pretty Sure it’s y=x+(-.8) haven’t done algebra in a bit. Sorry if wrong. :/
![\dfrac{ \dfrac{x+3}{4x^2-16} }{ \dfrac{2x^2+10x+12}{2x-4} }](https://tex.z-dn.net/?f=%20%5Cdfrac%7B%20%5Cdfrac%7Bx%2B3%7D%7B4x%5E2-16%7D%20%7D%7B%20%5Cdfrac%7B2x%5E2%2B10x%2B12%7D%7B2x-4%7D%20%7D%20)
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Write the divide fraction horizontally:
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![= \dfrac{x+3}{4x^2-16} \div \dfrac{2x^2+10x+12}{2x-4}](https://tex.z-dn.net/?f=%3D%20%5Cdfrac%7Bx%2B3%7D%7B4x%5E2-16%7D%20%5Cdiv%20%5Cdfrac%7B2x%5E2%2B10x%2B12%7D%7B2x-4%7D%20)
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Factorise the numerators and denominators when possible:
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![= \dfrac{x+3}{4(x+2)(x-2)} \div \dfrac{ 2(x + 3) (x + 2)}{2(x-2)}](https://tex.z-dn.net/?f=%3D%20%5Cdfrac%7Bx%2B3%7D%7B4%28x%2B2%29%28x-2%29%7D%20%5Cdiv%20%5Cdfrac%7B%202%28x%20%2B%203%29%20%28x%20%2B%202%29%7D%7B2%28x-2%29%7D%20)
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Convert the divide fraction to multiplication fraction
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![= \dfrac{x+3}{4(x+2)(x-2)} \times \dfrac{2(x-2)}{2(x+3)(x+2)}](https://tex.z-dn.net/?f=%3D%20%5Cdfrac%7Bx%2B3%7D%7B4%28x%2B2%29%28x-2%29%7D%20%5Ctimes%20%5Cdfrac%7B2%28x-2%29%7D%7B2%28x%2B3%29%28x%2B2%29%7D%20)
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Cancel the factors
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![= \dfrac{1}{4(x+2)} \times \dfrac{1}{(x+2)}](https://tex.z-dn.net/?f=%3D%20%5Cdfrac%7B1%7D%7B4%28x%2B2%29%7D%20%5Ctimes%20%5Cdfrac%7B1%7D%7B%28x%2B2%29%7D%20)
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Combine to single fraction
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