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3 years ago

What is the slope of the line passing through (-3, 5) and (5, -3)?

Mathematics

2 answers:

algol [13]3 years ago

8 0

Slope =-1. Just subtract the x points (-3-5) and the y points (5-(-3)) and divide the two. (-8/8)

bixtya [17]3 years ago

7 0

The slope should be -1

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What is 4.5w=5.1w-30 step by step please

vampirchik [111]

4.5w = 5.1w -30

4.5w - 5.1w = 5.1w - 5.1w -30 (subtracted 5.1w on both sides)

4.5w - 5.1w = -30 (next combine like terms)

-0.6w = -30 (next do the inverse operation of w)

w = -30 ÷ -0.6

w = 50 (it became positive cause minus and minus = positive)

so your final answer is: w = 50

Hope that helps:D

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3 years ago

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4 × (3 + 7) = (4 ×[]) + (4 ×[])

Naily [24]

Answer:

4 × (3 + 7) = (4 ×7) + (4 × 3)

Step-by-step explanation:

If you go by the order of PEMDAS you would do the parentheses first. 3 + 7 =10. 10 × 4 = 40. Then you would just use the distributive property and do (4× 7) + (4 × 3)

4 × 7 = 28 and 4 × 3 = 12 28 +12 =40

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3 years ago

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Nitella [24]

Answer: I think A

Step-by-step explanation:

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3 years ago

the cylinder has radius 4√3 and hight h. the total surface area of the cylinder is 56π√6. find the exact value of h giving the a

Arte-miy333 [17]

The area of the cylinder is a function of its height (h) and radius, ( $\mathbf{4\sqrt 3}$ )

The exact value of h is: $\mathbf{7\sqrt 2- 4\sqrt 3}$

The given parameters are:

$\mathbf{Area =56\pi\sqrt 6}$

$\mathbf{r=4\sqrt 3}$

The surface area of a cylinder is calculated as:

$\mathbf{Area = 2\pi rh + 2\pi r^2}$

Substitute values for Area

$\mathbf{56\pi\sqrt 6= 2\pi rh + 2\pi r^2}$

Divide through by pi

$\mathbf{56\sqrt 6= 2 rh + 2r^2}$

Substitute value for r

$\mathbf{56\sqrt 6= 2 (4\sqrt 3)h + 2(4\sqrt 3)^2}$

$\mathbf{56\sqrt 6= 8h\sqrt 3 + 2\times 48}$

$\mathbf{56\sqrt 6= 8h\sqrt 3 + 96}$

Collect like terms

$\mathbf{8h\sqrt 3 = 56\sqrt 6- 96}$

Make h the subject

$\mathbf{h = \frac{56\sqrt 6}{8\sqrt 3}- \frac{96}{8\sqrt 3}}$

$\mathbf{h = 7\sqrt 2- \frac{12}{\sqrt 3}}$

Rationalize

$\mathbf{h = 7\sqrt 2- \frac{12\sqrt 3}{3}}$

$\mathbf{h = 7\sqrt 2- 4\sqrt 3}$

Hence, the exact value of h is: $\mathbf{7\sqrt 2- 4\sqrt 3}$