Question

If you drop something from a height of 116 ft, the function h(t)=-16t^2 + 116 gives the height of the object after t seconds when will it hit the ground

Answer 1

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Answer 2

we are given

height function as

$h(t)=-16t^2+116$

Any object will hit the ground when height is zero

because at ground height will become 0

so, we can set h(t)=0

and then we can solve for t

$h(t)=-16t^2+116=0$

$-16t^2+116-116=0-116$

$-16t^2=0-116$

multiply both sides -1

$16t^2=116$

Divide both sides by 16

$\frac{16t^2}{16} =\frac{116}{16}$

$t^2 =\frac{116}{16}$

now, we can take sqrt both sides

$t=\sqrt{\frac{116}{16}}$

so, we get

$t=2.69258$

so, it will hit ground after 2.69258 seconds ...........Answer