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Lana71 [14]
3 years ago
14

What is the sloe and y intercept for tge graph of y-3x=15

Mathematics
1 answer:
marishachu [46]3 years ago
8 0
I believe the slope is 3 and the y-intercept is -15.
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A research program used a representative random sample of men and women to gauge the size of the personal network of older adult
My name is Ann [436]

Answer:

a. \mu=\bar x =14.6

b. The 95% CI for the population mean is (14.22, 14.98).

c. B. "The statement is incorrect. A correct statement would be​"One can be​ 95% confident that the true mean number of people named per person will fall in the interval computed in part b"

d. D. It does not impact the validity of the interpretation because the sampling space of the sample mean is approximately normal according to the Central Limit Theorem.

Step-by-step explanation:

a) The sample mean provides a point estimation of the population mean.

In this case, the estimation of the mean is:

\mu=\bar x =14.6

b) With the information of the sample we can estimate the

As the sample size n=2824 is big enough, we can aproximate the t-statistic with a z-statistic.

For a 95% CI, the z-value is z=1.96.

The sample standard deviation is s=10.3.

The margin of error of the confidence is then calculated as:

E=z\cdot s/\sqrt{n}=1.96*10.3/\sqrt{2824}=20.188/53.141=0.38

The lower and upper limits of the CI are:

LL=\bar x-z\cdot s/\sqrt{n}=14.6-0.38=14.22\\\\UL=\bar x+z\cdot s/\sqrt{n}=14.6+0.38=14.98

The 95% CI for the population mean is (14.22, 14.98).

c. "95% of the​ time, the true mean number of people named per person will fall in the interval computed in part b"

The right answer is:

B. "The statement is incorrect. A correct statement would be​"One can be​ 95% confident that the true mean number of people named per person will fall in the interval computed in part b"

The confidence interval gives bounds within there is certain degree of confidence that the true population mean will fall within.

It does not infer nothing about the sample means or the sampling distribution. It only takes information from a sample to estimate a interval for the population mean with certain degree of confidence.

d. It is unlikely that the personal network sizes of adults are normally distributed. In​ fact, it is likely that the distribution is highly skewed. If​ so, what​ impact, if​ any, does this have on the validity of inferences derived from the confidence​ interval?

The answer is:

D. It does not impact the validity of the interpretation because the sampling space of the sample mean is approximately normal according to the Central Limit Theorem.

The reliability of a confidence interval depends more on the sample size, not on the distribution of the population. As the sample size increases, the absolute value of the skewness and kurtosis of the sampling distribution decreases. This sample size relationship is expressed in the central limit theorem.

4 0
3 years ago
What is the missing reason from the following proof? <br><br> (The answer is NOT C.)
Vlada [557]

Answer:

its corresponding angles postulate

Step-by-step explanation:


6 0
3 years ago
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HI I NEED HELP ASAP!! I NEED HELP ON #10!! SOMEONE TELL ME WHAT IT IS PLZ!!
Helga [31]
The answer is -257 feet
5 0
3 years ago
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Anya graphed the line (y−2)=3(x−1) on the coordinate grid.
aliya0001 [1]

The slope of Anya’s line on the graph is 3

<h3>How to determine the slope of the line?</h3>

The equation is given as:

(y−2)=3(x−1)

Remove brackets

y − 2 = 3x − 3

Add 2 to both sides

y = 3x − 1

A linear equation is represented as:

y = mx + c

Where m represents the slope;

By comparison, m = 3

Hence, the slope of Anya’s line is 3

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In a random sample of 62 professional actors, it was found that 40 were extroverts. Please find the point estimate, 95% confiden
den301095 [7]

The point Estimate is 0.645 , the confidence interval is (0.525 ,0.764).

<h3>What is Point Estimate ?</h3>

The point estimate is the proportion of success in the sample.

From the data given

p = 40/62

p = 0.645

The point Estimate is 0.645

(b) Confidence interval for true proportion is

\rm {p -Z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}  , p +Z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}

For 95 % Z = 1.96

p =0.645

1-p = 0.355

putting the values

\rm {0.645 -1.96 \sqrt{\dfrac{0.645\times0.355}{62}}  , {0.645 +1.96 \sqrt{\dfrac{0.645\times0.355}{62}} \\

(0.525 , 0.764)

Lower Limit = 0.525

Upper Limit = 0.764

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