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2 years ago

Let f(t) ANSWER: 1+ = t² - 1 t+3 Find f'(1)

Mathematics

1 answer:

Luda [366]2 years ago

4 0

Answer:

f(1) = 3

Step-by-step explanation:

f(t) = t² - 1t + 3

we want to find f(1)

all we have to do is replace the t's with 1 and evaluate

f(1) = (1)² - 1(1) + 3

evaluate exponent 1² = 1

f(1) = 1 - 1(1) + 3

multiply

f(1) = 1 - 1 + 3

subtract

f(1) = 3

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Write each expression as an algebraic (nontrigonometric) expression in u, u > 0.

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Step-by-step explanation:

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Simplify. Therefore:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

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Let f(t) ANSWER: 1+ = t² - 1 t+3 Find f'(1)​

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